At ieee ISSCC today AMD revealed that a one module (two "core") Bulldozer will have 213 million transistors and measure just 30.9 square mm including cache. This means AMD's 32nm transistors are packed much more tightly than on Intel's 32nm procs.
for reference, here's Intel's 32nm procs:
Gulftown: 1.17b transistors, 240mm^2 = 4.875million transistors/mm^2
Clarkdale: 384m transistors, 81mm^2 = 4.74million transistors/mm^2
Sandy Bridge 4C: 996m transistors, 216mm^2 = 4.611million transistors/mm^2
Sandy Bridge 2C: 504m transistors, 131mm^2 = 3.85million transistors/mm^2
and here's Bulldozer:
231m transistors, 31mm^2 = 7.45million transistors/mm^2
I know the node name (32nm) is really a marketing label but this means AMD is laying down transistors at about 166% the density of Intel. Could this be an AMD advantage at last? Or did they make sacrifices in other characteristics of the chip? In any case, at 31mm^2 these things should be CHEAP, that's like 6mm^2 bigger than Atom.
for reference, here's Intel's 32nm procs:
Gulftown: 1.17b transistors, 240mm^2 = 4.875million transistors/mm^2
Clarkdale: 384m transistors, 81mm^2 = 4.74million transistors/mm^2
Sandy Bridge 4C: 996m transistors, 216mm^2 = 4.611million transistors/mm^2
Sandy Bridge 2C: 504m transistors, 131mm^2 = 3.85million transistors/mm^2
and here's Bulldozer:
231m transistors, 31mm^2 = 7.45million transistors/mm^2
I know the node name (32nm) is really a marketing label but this means AMD is laying down transistors at about 166% the density of Intel. Could this be an AMD advantage at last? Or did they make sacrifices in other characteristics of the chip? In any case, at 31mm^2 these things should be CHEAP, that's like 6mm^2 bigger than Atom.
