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basic algebra help at 5am!

Y

YayYay

Senior member
I'm trying to solve a problem and I can't see how this number is derived.

1,287(1+g)^50=2,457

the prof has g at .0013

I come up with a much higher number.

 
Divide both sides by 1287:

(1 + g)^50 = 2457/1287 = 1.909090

Then, take the 50th root of both sides.

1 + g = (1.90909090)^(1/50) = 1.0130165

Subtract 1 from both sides:

g = 0.013.
 
Originally posted by: hypn0tik
Divide both sides by 1287:

(1 + g)^50 = 2457/1287 = 1.909090

Then, take the 50th root of both sides.

1 + g = (1.90909090)^(1/50) = 1.0130165

Subtract 1 from both sides:

g = 0.013.
Click to expand...


what he said
 
Thanks for all the help guys! I meant to type .013 so the prof was right. I was just messing up my algebra.
 
Originally posted by: lilcam
Originally posted by: hypn0tik
Divide both sides by 1287:

(1 + g)^50 = 2457/1287 = 1.909090

Then, take the 50th root of both sides.

1 + g = (1.90909090)^(1/50) = 1.0130165

Subtract 1 from both sides:

g = 0.013.
Click to expand...


what he said
Click to expand...

:thumbsup:

 
Did you try to take the 50th root first and then do the dividing? I couldn't remember which order you do them in but the ^50 only applies to what's in the parenthesis so you have to do the dividing first to get the 1,287 out of there.
 
of course the professor is right. not cause he's the smartest guy in the room, but because he has an answer key.....
 
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