basic algebra help at 5am!

[YayYay]

I'm trying to solve a problem and I can't see how this number is derived.

1,287(1+g)^50=2,457

the prof has g at .0013

I come up with a much higher number.

 

[Tu13erhead]

.013?

 

[hypn0tik]

Divide both sides by 1287:

(1 + g)^50 = 2457/1287 = 1.909090

Then, take the 50th root of both sides.

1 + g = (1.90909090)^(1/50) = 1.0130165

Subtract 1 from both sides:

g = 0.013.

 

[VTHodge]

Originally posted by: Tu13erhead
.013?

Agree

 

[hypn0tik]

Originally posted by: VTHodge

Originally posted by: Tu13erhead
.013?

Agree

Yep.

 

[Aves]

I also got .013 rather than .0013

 

[BChico]

Originally posted by: Tu13erhead
.013?

I concur.

 

[LuckyTaxi]

Originally posted by: hypn0tik
Divide both sides by 1287:

(1 + g)^50 = 2457/1287 = 1.909090

Then, take the 50th root of both sides.

1 + g = (1.90909090)^(1/50) = 1.0130165

Subtract 1 from both sides:

g = 0.013.

what he said

 

[YayYay]

Thanks for all the help guys! I meant to type .013 so the prof was right. I was just messing up my algebra.

 

[Vegitto]

Originally posted by: lilcam

Originally posted by: hypn0tik
Divide both sides by 1287:

(1 + g)^50 = 2457/1287 = 1.909090

Then, take the 50th root of both sides.

1 + g = (1.90909090)^(1/50) = 1.0130165

Subtract 1 from both sides:

g = 0.013.

what he said

:thumbsup:

 

[Kelemvor]

Did you try to take the 50th root first and then do the dividing? I couldn't remember which order you do them in but the ^50 only applies to what's in the parenthesis so you have to do the dividing first to get the 1,287 out of there.

 

[reboos]

0.0130165303012

 

[habib89]

of course the professor is right. not cause he's the smartest guy in the room, but because he has an answer key.....

 

[ActuaryTm]

• Post problem you haven't a clue how to solve.
• Post wrong answer.
• Wait.
• ...
• Profit.

 

[manohartvs]

Originally posted by: habib89
of course the professor is right. not cause he's the smartest guy in the room, but because he has an answer key.....

that is absolutely correct