bash: compare a variable to a text string

[imported_Frank]

Hello!

I'd like to know how, in my bash script, I can compare a variable to a text string.. just like in php:

if ($blabla == "ohohoh") { ... }

The variable needs to be compared to a text string, no numbers 🙂


Thanks all! Frank

 

[mikecel79]

I know next to nothing about bash but this will probably help.Linky. 15 seconds of google searching found that for me....

 

[imported_Frank]

Thanks for searching but I've been working on this problem for more than two hours and, according to this how-to:

if [ "$bla" = "blabla" ]; then

should work as asked, but in fact, all it says is an error such as:

./blabla: line 16: [blabla: command not found

This error is all I could get in the hours I worked on this problem 🙁


Frank

 

[n0cmonkey]

if [ "$TYPE" == "smb" ] ; then

works for me. In the script I have this in, TYPE is set by the user.

 

[Barnaby W. Füi]

[" is not at all the same as [ ". That's like trying to do ls*.jpg instead of ls *.jpg

Look at the output of: ls -l `which [` edit: nm on that

well, [ is the same command as "test". It's a command, not a shell syntax construct.

 

[n0cmonkey]

I swear there was a "[" on one system or another... 😛

 

[Barnaby W. Füi]

Oh, it's there (on debian at least), but it's just not linked to test like I thought it was.

 

[n0cmonkey]

Sorry, I was confused. But it doesn't appear in a `which [` on Solaris, but it works (using bash anyways). 😛

 

[Barnaby W. Füi]

Yeah, it's a builtin in probably most shells.

 

[imported_Frank]

Ahhh, needed a blank space between the " and the [ ]'s... Can't beleive I lost all this time on a dumb problem like this one :S

Thanks again folks!