DisgruntledVirus
Lifer
- Dec 26, 2007
- 11,782
- 2
- 76
Originally posted by: cubby1223
x=distance when the first walker was picked up
y=distance when the biker began walking
65-x=y
x @ 5kmph + y @ 50kmph = (2y+(65-2x)) @ 50kmph
whoever wants to work it out, I don't care. Only thing I'd like to know is, the motorbike always runs at a constant 50kmph, must have been rough when the one was shoved off the bike at such high velocity.
edit - I'm failing to see how this is considered "higher" math. :confused;
Well you know those politicians these days, they don't want no child left behind even though they were left behind in 4th grade.