Are human being inherently illogical? Try this logic test.

[azazyel]

There should be 24 combinations of 4.

Duckers do you use Netscape?

 

[The Wildcard]

I just picked A. Said something like 50% are correct now.

 

[azazyel]

I hope this wasn't some kind of survey!

 

[Mark R]

Not a survey, just an experiment to see how logically people think.

Oh, and the only reason the tally is close to 50% is become someone was very bored and submitted the same answer about 90 times.

 

[EmperorNero]

<< This statement makes no mention of how large the &quot;set&quot; of cards is, and only states that 4 are presented. Therefore, there is no way to test the assertion that vowels are ALWAYS paired with odd numbers other than checking all vowels in the entire unknown quantity of cards. >>



I think formatc: is absolutely correct when he said the above. so there's a loophole in your directions, maybe you can change it to:



<< The following set of cards has letters on one side, and numbers on the other side. You are told that vowels are always paired with odd numbers. Which cards must be turned over to test this assertion? >>

 

[Mark R]

OK.

 

[pen^2]

GoofusMaximus, thats what i did, no clue if i got it right tho...

 

[Ornery]

&quot;I tell you the answer in a couple of days.&quot;

Ahem... :disgust:

 

[BigSmooth]

It said I got it right and something like 40% of people have gotten it right.

 

[BoberFett]

I can't get to the page. Apparently the webmaster is suffering from a lack of logical thinking.

 

[mosdef]

Just follow the statement: all vowels are paired with odd numbers. Note that this is not the same as all odd numbers are paired with vowels. Then also check the contrapositive: All non-odd numbers are paired with non-vowels.

-mosdef

 

[Passions]

There is something wrong with the directions because what reason would you have to turn over A, if in the directions it already told you that vowels are paired with odd numbers. Therefore, there is NO reason to flip A since you are told that condition.

 

[BoberFett]

To test that, you'd have to flip all the cards. What's stopping the 'B' from having an 'E' on the back. Unless you flip the B, you won't know for sure that the statement is true.

 

[piku]

A and 2 CANNOT be correct!

You must flip over A and 1 in order for this to work.

If the answer was A and 2, then under 1 could be X or T or something, making the statement &quot;vowels are always paired with odd numbers&quot; incorrect. To make sure it is correct you must also flip over the 1.

No other card is relevent, because it doesnt matter what is paired with B or 2: nothing is said about their pairings.

 

[piku]

<< all vowels are paired with odd numbers. Note that this is not the same as all odd numbers are paired with vowels. >>



Yes it is the same. If right is always to the right of left, left would always be to the left of right.

Or 2 always follows 1, so 1 always preceeds 2. Or A is always before B, so B is always after A. Its the same thing.

 

[BoberFett]

piku

I disagree, B and 2 are important. What if all the cards had E on the back? I still say you can't test this assertion until you flip all cards.

 

[FrontlineWarrior]

i think GoofusMaximus got it right.

 

[piku]

If there are E's behind every card then the statement is 100% true. Why?

No mention is made if vowels can be used more than once.
No mention is made if vowels can or cannot be behind even numbers.

Therefore, all that matters is if there are vowels behind the odd numbers, which there would be if only E's were behind the cards.

It does mention that cards have to have numbers on one side and letters on the other. You cannot have a double letter or double number combination.

 

[piku]

Ok, in Algebra, you have a statement X = 2. Think of that as vowels = odd. The statement 2 = X is the SAME value, and completley true in Algebra. So why wouldnt odd = vowels work?

 

[BoberFett]

<< It does mention that cards have to have numbers on one side and letters on the other. >>

Well, that would change things. I was pretty sure I read the text carefully, can I get back to the page with the puzzle and instructions again? Now all it gives me is the results.

 

[BA]

woohoo! I am correct. Discrete must be paying off.

 

[piku]

Bober, here is the text :A set of cards has letters on one side, and numbers on the other side.

Therefore there MUST be a letter on one side and a number on the other.

 

[Pretender]

LOL, I just didn't check any boxes and it gave me the answer (A + 2)

I'm too tired to bother thinking, logic dictates that if I get it wrong, the next page will tell me the answer.

 

[BoberFett]

Nevermind me then.

 

[konichiwa]

Doesn't seem so hard to me. :Q

Hey BTW did you write this page yourself? I'm interested in ASP programming...easy to do? (I know, totally OT )