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arctan = 1/tan right?

yeah

actually i dont know cause its been years since i have taken trig, but i do remember the book being helpful
 


<< Technically, it's the integral of 1/(1+x^2) with respect to x. >>



actually its an infinite series, as is pi, e, sin, cos, etc
 


<<

<< Technically, it's the integral of 1/(1+x^2) with respect to x. >>



actually its an infinite series, as is pi, e, sin, cos, etc
>>



Uhhh, it's BOTH...the Taylor series expansion is a way of expressing it explicitly. I have merely expressed it compactly.
 
the notation tan^-1 (X) is simply arctan (X). This is odd, since tan^2 (X) is actually (tan X)^2

I dislike the notation, but anyway, arctan X (or tan^-1 (X)) helps you to go from angle measure back to side proportion. For example, tan (30) (or tan pi/6 for you radian lovers) is equal to 1/2, since the opposite side will be half the length of the adjacent side.

Now, arctan (1/2) is 30 (or pi/6) because this brings you from opposite/adjacent side proportion back to the angle measure.
 
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