AP Calc problem. Help?

[Mo0o]

Hey, i got a questions regarding antiderivatives

what is the anti of

(1/79)(768+23t-t^2)

 

[Poncherelli]

(1/79) (768t+(23/2)t^2-(t/3)^3) +C

I think....

 

[minendo]

(1/79)(768t + 23/2 t^2 - (t^3)/3) + C

 

[minendo]

doh i forgot the + c

 

[Mo0o]

wow, you guys ar egood

 

[soccerbud34]

yup (1/79) (768t+(23/2)t^2-(t/3)^3) +C
is what i got

 

[Mo0o]

hey, but waut, inthe quotient rule, you square the denominator when you take the derivative so shouldn't it be for the anti? 1/(79^(1/2) )?

 

[minendo]

no because if you actually multiply the original problem out, you still end up with the 1/79 in the answer

 

[minendo]

multiplying the problem by 1/79 is just like multiplying the problem by 1, you can ignore it in the problem

it would look like this

(768/79) + (23/79)t - (t^2)/79
(768/79)t + (23/79x2)t^2 - (t^3)/79x3 + C
and factoring out 1/79 gives you the answer