# Another Math Wiz question. Come on in. 2 questions

#### BAMAVOO

##### Diamond Member
Solve this one.

1/x+1/(x-1) = 5/2x

and this one

y/(y-4)-(5/3) = 4/(y-4)

BUMP

#### BigJ

##### Lifer
For the first one, find the LCD and solve. For the second one, get all the numbers divided by y-4 on the same side then solve. Not very hard questions.

#### BigPoppa

##### Golden Member
First one:
Multiply 1/x by (x-1)/(x-1) and 1/(x-1) by x/x. Easy to solve from there.

Second one:
Not solvable? I'm getting 1 = 5/3.

##### Member
Originally posted by: BigPoppa
First one:
Multiply 1/x by (x-1)/(x-1) and 1/(x-1) by x/x. Easy to solve from there.

Second one:
Not solvable? I'm getting 1 = 5/3.
It's solvable...I got an integer answer. Not really that hard (then again, I have a bachelor's in math).

#### minendo

##### Elite Member
Originally posted by: BigPoppa
First one:
Multiply 1/x by (x-1)/(x-1) and 1/(x-1) by x/x. Easy to solve from there.

Second one:
Not solvable? I'm getting 1 = 5/3.
It's solvable...I got an integer answer. Not really that hard (then again, I have a bachelor's in math).
Is it just -4?

#### DXM

##### Senior member
I got y = +4 for the second one.

#### minendo

##### Elite Member
Originally posted by: DXM
I got y = +4 for the second one.
That gives you a divide by 0 error on the right side of the equation.

#### waffel

##### Member
I can't get the second one, I don't think it has a solution
y/(y-4) - 5/3 = 4/(y-4)
(y-4)/(y-4) = 5/3
1 = 5/3?

##### Member
Originally posted by: minendo
Originally posted by: DXM
I got y = +4 for the second one.
That gives you a divide by 0 error on the right side of the equation.
Very true. I also got y=-4.

#### pray4mojo

##### Diamond Member
Originally posted by: waffel
I can't get the second one, I don't think it has a solution
y/(y-4) - 5/3 = 4/(y-4)
(y-4)/(y-4) = 5/3
1 = 5/3?

Woops I bombed it. Got confused with the way the equation is written.

#### waffel

##### Member
Originally posted by: minendo
Originally posted by: DXM
I got y = +4 for the second one.
That gives you a divide by 0 error on the right side of the equation.
Very true. I also got y=-4.
That doesn't work, if you plug that back in you get
1/2 - 5/3 = -1/2
?

#### Goosemaster

##### Lifer
you guys jsut did his homework....

#### DXM

##### Senior member
Originally posted by: minendo
Originally posted by: DXM
I got y = +4 for the second one.
That gives you a divide by 0 error on the right side of the equation.
You're right minendo. Funny thing is, I just worked out the problem twice and got +4 twice. So I either need to be sent back to Algebra I or I'm missing a negative sign somewhere.

#### waffel

##### Member
Originally posted by: pray4mojo
Originally posted by: waffel
I can't get the second one, I don't think it has a solution
y/(y-4) - 5/3 = 4/(y-4)
(y-4)/(y-4) = 5/3
1 = 5/3?
y = -6
I don't know how you got from y/(y-4) - 5/3 = 4/(y-4) to (y-4)/(y-4) = 5/3.
y/(y-4) - 5/3 = 4/(y-4)
add 5/3 to both sides, subtract 4/(y-4) from both sides
y/(y-4) - 4/(y-4) = 5/3
combine terms
(y-4)/(y-4) = 5/3

##### Member
Originally posted by: waffel
I can't get the second one, I don't think it has a solution
y/(y-4) - 5/3 = 4/(y-4)
(y-4)/(y-4) = 5/3
1 = 5/3?
Okay, my husband the math teacher agrees with you.

y/(y-4) - (5/3) = 4/(y-4)
y - (5/3)(y-4) = 4
y - (5/3)y + (20/3) = 4
(1 - 5/3)y = 4 - (20/3)
-(2/3)y = -(8/3)
y = -(8/3)*-(3/2)
y = 4

Since the (possible) solution y = 4 is undefined (can't divide by zero), there is no solution.

#### rgwalt

##### Diamond Member
Originally posted by: waffel
Originally posted by: pray4mojo
Originally posted by: waffel
I can't get the second one, I don't think it has a solution
y/(y-4) - 5/3 = 4/(y-4)
(y-4)/(y-4) = 5/3
1 = 5/3?
y = -6
I don't know how you got from y/(y-4) - 5/3 = 4/(y-4) to (y-4)/(y-4) = 5/3.
y/(y-4) - 5/3 = 4/(y-4)
add 5/3 to both sides, subtract 4/(y-4) from both sides
y/(y-4) - 4/(y-4) = 5/3
combine terms
(y-4)/(y-4) = 5/3
Yep, the equation has no solution.

R