Another Math Wiz question. Come on in. 2 questions

[BAMAVOO]

Solve this one.

1/x+1/(x-1) = 5/2x

and this one

y/(y-4)-(5/3) = 4/(y-4)

 

[Lager]

BUMP

 

[BigJ]

For the first one, find the LCD and solve. For the second one, get all the numbers divided by y-4 on the same side then solve. Not very hard questions.

 

[eakers]

 

[BigPoppa]

First one:
Multiply 1/x by (x-1)/(x-1) and 1/(x-1) by x/x. Easy to solve from there.

Second one:
Not solvable? I'm getting 1 = 5/3.

 

[GrouchyLadybug]

Originally posted by: BigPoppa
First one:
Multiply 1/x by (x-1)/(x-1) and 1/(x-1) by x/x. Easy to solve from there.

Second one:
Not solvable? I'm getting 1 = 5/3.

It's solvable...I got an integer answer. Not really that hard (then again, I have a bachelor's in math).

 

[minendo]

Originally posted by: GrouchyLadybug

Originally posted by: BigPoppa
First one:
Multiply 1/x by (x-1)/(x-1) and 1/(x-1) by x/x. Easy to solve from there.

Second one:
Not solvable? I'm getting 1 = 5/3.

It's solvable...I got an integer answer. Not really that hard (then again, I have a bachelor's in math).

Is it just -4?

 

[DXM]

I got y = +4 for the second one.

 

[minendo]

Originally posted by: DXM
I got y = +4 for the second one.

That gives you a divide by 0 error on the right side of the equation.

 

[waffel]

I can't get the second one, I don't think it has a solution
y/(y-4) - 5/3 = 4/(y-4)
(y-4)/(y-4) = 5/3
1 = 5/3?

 

[GrouchyLadybug]

Originally posted by: minendo

Originally posted by: DXM
I got y = +4 for the second one.

That gives you a divide by 0 error on the right side of the equation.

Very true. I also got y=-4.

 

[pray4mojo]

Originally posted by: waffel
I can't get the second one, I don't think it has a solution
y/(y-4) - 5/3 = 4/(y-4)
(y-4)/(y-4) = 5/3
1 = 5/3?

Woops I bombed it. Got confused with the way the equation is written.

 

[waffel]

Originally posted by: GrouchyLadybug

Originally posted by: minendo

Originally posted by: DXM
I got y = +4 for the second one.

That gives you a divide by 0 error on the right side of the equation.

Very true. I also got y=-4.

That doesn't work, if you plug that back in you get
1/2 - 5/3 = -1/2
?

 

[Goosemaster]

you guys jsut did his homework....

 

[DXM]

Originally posted by: minendo

Originally posted by: DXM
I got y = +4 for the second one.

That gives you a divide by 0 error on the right side of the equation.

You're right minendo. Funny thing is, I just worked out the problem twice and got +4 twice. So I either need to be sent back to Algebra I or I'm missing a negative sign somewhere. 😉

 

[waffel]

Originally posted by: pray4mojo

Originally posted by: waffel
I can't get the second one, I don't think it has a solution
y/(y-4) - 5/3 = 4/(y-4)
(y-4)/(y-4) = 5/3
1 = 5/3?

y = -6
I don't know how you got from y/(y-4) - 5/3 = 4/(y-4) to (y-4)/(y-4) = 5/3.

y/(y-4) - 5/3 = 4/(y-4)
add 5/3 to both sides, subtract 4/(y-4) from both sides
y/(y-4) - 4/(y-4) = 5/3
combine terms
(y-4)/(y-4) = 5/3

 

[GrouchyLadybug]

Originally posted by: waffel
I can't get the second one, I don't think it has a solution
y/(y-4) - 5/3 = 4/(y-4)
(y-4)/(y-4) = 5/3
1 = 5/3?

Okay, my husband the math teacher agrees with you.

y/(y-4) - (5/3) = 4/(y-4)
y - (5/3)(y-4) = 4
y - (5/3)y + (20/3) = 4
(1 - 5/3)y = 4 - (20/3)
-(2/3)y = -(8/3)
y = -(8/3)*-(3/2)
y = 4

Since the (possible) solution y = 4 is undefined (can't divide by zero), there is no solution.

 

[rgwalt]

Originally posted by: waffel

Originally posted by: pray4mojo

Originally posted by: waffel
I can't get the second one, I don't think it has a solution
y/(y-4) - 5/3 = 4/(y-4)
(y-4)/(y-4) = 5/3
1 = 5/3?

y = -6
I don't know how you got from y/(y-4) - 5/3 = 4/(y-4) to (y-4)/(y-4) = 5/3.

y/(y-4) - 5/3 = 4/(y-4)
add 5/3 to both sides, subtract 4/(y-4) from both sides
y/(y-4) - 4/(y-4) = 5/3
combine terms
(y-4)/(y-4) = 5/3

Yep, the equation has no solution.

R