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AMD's DDR2 Update

Having just read the Anandtech news article on the new Socket M2 with DDR2 support it left me with a few questions.

DDR2 is supposed to take less power than DDR(1). So why does the TDP increase by so much? Is this a result of all the logic required to use DDR2? Or is it a result of those data visualization features?

-Kevin
 
Could be a number of things. More cache, larger memory controller (maybe they added something to help reduce the extra latency of DDRII Ram), or extra goodies we dont' yet know about. Another thing thats possible is that they had to increase the speed of the memory controller running to let it run the DDRII at 667mhz. I dont' know if thats at all logical, but its the best I can do. 🙂
 
AMD lies on thier TDP's I have no faith in them. They said 3800 uses 78W xbit and others measured 48W.. thier way overrate for some reason... Anyay do you have a link?
 
Originally posted by: Zebo
AMD lies on thier TDP's I have no faith in them. They said 3800 uses 78W xbit and others measured 48W.. thier way overrate for some reason... Anyay do you have a link?

I think AMD's TDP is measures as peak power output, ie maximum it can output/would ever output, and not an average output.
 
Originally posted by: Gamingphreek
Having just read the Anandtech news article on the new Socket M2 with DDR2 support it left me with a few questions.

DDR2 is supposed to take less power than DDR(1). So why does the TDP increase by so much? Is this a result of all the logic required to use DDR2? Or is it a result of those data visualization features?

-Kevin

Because of the way AMD assigns TDP and what TDP actually is...

1. TDP isn't the actual power usage, it's a cooling guideline for OEMs. In AMD's case, it represents the absolute max theoretical power for an entire line of processors. (in other words, you won't ever actually hit the TDP)

2. Orleans will scale to higher clockspeeds than Venice or San Diego, so the product line needs to have a higher TDP because later models will run at faster speeds.
 
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