Bacteria Growth - A colony of bacteria is grown underideal conditions in a laboratory so that the population increases exponentially with time. At the end of 3 h there are 10,000 bacteria. At the end of 5 h there are 40,000 bacteria. How many bacteria were present initially?
What I did:
I used a generic function like this: y = (y initial)e^(-kt)
I made did:
40,000 = 10,000e^(2k)
Solved for k, k = 1n(4) / 2
Plugged k into this:
10,000 = Xe^(3k)
X = 1250
1250 bacteria were there initially?
Thanks
What I did:
I used a generic function like this: y = (y initial)e^(-kt)
I made did:
40,000 = 10,000e^(2k)
Solved for k, k = 1n(4) / 2
Plugged k into this:
10,000 = Xe^(3k)
X = 1250
1250 bacteria were there initially?
Thanks
Facebook
Twitter