Originally posted by: Narmer
I'm studying this:
link
We we're given this example in class: (12)(23) = (123)
: (123)(132) = I.
Anybody know how this works?
ooh you might get to do caley graphs, those were fun. Yah, this is function composition.
lets say that (123) = f and (132) = g
so you want to basically permuate all the numbers, lets start with 1
so reading right to left (b/c function composition) we find 1 which is equivalent to saying what happens with f(g(1))...well g(1) goes to 3 (the 3 to the right of the 1) so now we have f(3) and that three goes to 1...so basically if you start with 1 you end with 1 and it can be written as (1)
Now the same thing happens with the rest...we covered 1, so lets go find 2.
f(g(2)) = f(1) = 2 ...so again 2 goes to 2...(2)
f(g(3)) = f(2) = 3 ...(3)
so you could write it as (123)(132) = (1)(2)(3) or as your professor put it.
hope that helps somewhat.
and for the first one...lets start at 2 to spice things up : P
so f = (12) g = (23)
f(g(2)) = f(3) which is nothing so that's why you just have your 2 going to 3
now f(g(3) = f(2) = 1 so 3 goes to 1 ...i.e. (231) which says 1 goes to 2, 2 goes to 3 and three goes to 1
just thought I'd show you that you can write the things in different ways and have it mean the same thing.