algebra problem

[coder1]

I'm having trouble simplifying this problem.

(2/x) + (3/2x)
------------------
(4/3x) - (2/2x)


I keep getting 21/2

But I know thats wrong, any ideas?

Thanks in advance

 

[dullard]

I also get 21/2.

 

[blackdogdeek]

Originally posted by: dullard
I also get 21/2.

 

[notfred]

I have no idea what that problem is suppsoed to be. Something like this: (23/x2x)/(42/3x2x)?

I really have no idea.

 

[coder1]

weird, according to my answer sheet it says -21/4 is the answer

 

[dullard]

I'm assuming you mean this by your formatting:
((2/x)+(3/2x)) / ((4/3x)-(2/2x)).

Multiply both top and bottom by x:
(2+3/2) / (4/3-2/2).

Combine the top and bottom fractions:
(7/2) / (1/3).

Multiply both top and bottom by 3:
(21/2) / (1).

Simplfy:
21/2.

 

[coder1]

I tried to change the format to better represent the problem.

sorry for the confusion

 

[tkim]

wuts the answer suppose to be?

 

[notfred]

yeah, I got 21/2 also. Maybe the answer key is wrong.

 

[coder1]

interesting, according to the answer sheet its suppose to be -21/4

 

[fumbduck]

i just did it algebraically and then using calculus, 21/2 both times.

 

[coder1]

Thanks for all the help guys.

 

[DrPizza]

fastest way is to multiply the top and bottom by the common denominator.... 6x

Doing so will give you
12 + 9
---------
8 - 6

and, that, according to a math teacher, is 21/2

 

[dionx]

Originally posted by: blackdogdeek

Originally posted by: dullard
I also get 21/2.