W Who27 Junior Member Dec 11, 2001 17 0 0 Nov 18, 2002 #1 Could someone give me some guidance on how to simplify this expression: (tan(y) + cot(y)) / csc2(y) That 2 is a square. Thanks for your help.
Could someone give me some guidance on how to simplify this expression: (tan(y) + cot(y)) / csc2(y) That 2 is a square. Thanks for your help.
minendo Elite Member Aug 31, 2001 35,560 22 81 Nov 18, 2002 #2 tan = 1/cot csc = 1/sin tan = sin/cos (i think) sin2 + cos2 = 1 Use those and go from there.
H Hanpan Diamond Member Aug 17, 2000 4,812 0 0 Nov 18, 2002 #3 The answer is tan(y) I will give some intermediate steps. The rest is up to you. (I am not bothering to write the argument y) ... sin^2(sin/cos+cos/sin) ... then sin(sin^2/cos + cos^2/cos) ... = tan(y)
The answer is tan(y) I will give some intermediate steps. The rest is up to you. (I am not bothering to write the argument y) ... sin^2(sin/cos+cos/sin) ... then sin(sin^2/cos + cos^2/cos) ... = tan(y)
W Who27 Junior Member Dec 11, 2001 17 0 0 Nov 18, 2002 #4 Ohhhhh, I get it now, I had some mental block or something, thanks so much for your help.