Ahh, simple probability problem I can't get

[Syringer]

Jilll's average bowling score is 170 with standard deviation of 20, Jack is 160 and 15.

What's the prob that Jack's score is higher?

 

[Iron Woode]

why are there 3 L's in Jill's name?

 

[mobobuff]

15/spider

 

[mitaiwan82]

Originally posted by: Iron Woode
why are there 3 L's in Jill's name?

BYOBB

 

[Iron Woode]

Originally posted by: mitaiwan82

Originally posted by: Iron Woode
why are there 3 L's in Jill's name?

BYOBB

What's the extra B for?

 

[Syringer]

Lisa: Come to Homer's BBBQ, the extra 'B' is for BYOBB.
Bart: What's that extra B for?
Homer: That's a typo.

 

[Syringer]

Now back to statS!

 

[HomeBrewerDude]

2 sample t test or something like that

 

[beer]

Are we assuming normal gaussians here?

You have your mean
you have your variance

convert them into standard gassians and use the CDF table for the random variables of their scores

 

[TuxDave]

Originally posted by: Syringer
Jilll's average bowling score is 170 with standard deviation of 20, Jack is 160 and 15.

What's the prob that Jack's score is higher?

Find the probability that Jack-Jill is greater than 0. You subtract the means, you add the variance, and then use a Z-table.

 

[Yo Ma Ma]

Originally posted by: Iron Woode
why are there 3 L's in Jill's name?

That's what makes it such a tricky question. Those wacky profs.

 

depends on jacks efforts in the attempt to get laid that night

if he's goin for nook, he's gonna let her win

 

[KnickNut3]

Originally posted by: TuxDave

Originally posted by: Syringer
Jilll's average bowling score is 170 with standard deviation of 20, Jack is 160 and 15.

What's the prob that Jack's score is higher?

Find the probability that Jack-Jill is greater than 0. You subtract the means, you add the variance, and then use a Z-table.

:thumbsup:

 

[Deeko]

Originally posted by: mobobuff
15/spider

<3

 

[iamme]

wtf are they doing bowling??? there are pails of water to be fetched!! :|

 

[Iron Woode]

Originally posted by: troytime
depends on jacks efforts in the attempt to get laid that night

if he's goin for nook, he's gonna let her win

Jack and Jill
went up the hill.
each with a buck and a quarter.
Jill came down with $2.50.......

 

[Syringer]

Originally posted by: TuxDave

Originally posted by: Syringer
Jilll's average bowling score is 170 with standard deviation of 20, Jack is 160 and 15.

What's the prob that Jack's score is higher?

Find the probability that Jack-Jill is greater than 0. You subtract the means, you add the variance, and then use a Z-table.

You're a geeeeeeeeniusss!

 

[KnickNut3]

Originally posted by: troytime
depends on jacks efforts in the attempt to get laid that night

if he's goin for nook, he's gonna let her win

Definitely. His score is NOT a random variable--it is inversely proportional to her hotness.

 

[beer]

Originally posted by: KnickNut3

Originally posted by: troytime
depends on jacks efforts in the attempt to get laid that night

if he's goin for nook, he's gonna let her win

Definitely. His score is NOT a random variable--it is inversely proportional to her hotness.

That sounds like a conditional RV to me.
Solve for the joint PDF! They're obviously not indepedent, so you're stuck trying to solve for the marginal then...

 

Originally posted by: beer

Originally posted by: KnickNut3

Originally posted by: troytime
depends on jacks efforts in the attempt to get laid that night

if he's goin for nook, he's gonna let her win

Definitely. His score is NOT a random variable--it is inversely proportional to her hotness.

That sounds like a conditional RV to me.
Solve for the joint PDF! They're obviously not indepedent, so you're stuck trying to solve for the marginal then...

but if you bring a joint into the picture, jack being high may alter the array of methods used in getting the nook

 

[aplefka]

Originally posted by: troytime
depends on jacks efforts in the attempt to get laid that night

if he's goin for nook, he's gonna let her win

:thumbsup: