y is (20/3) and x is (10/3)!!
Work:
Eq 1: x+y = 10
Eq 2: x = 0.5y
We can immediately see that x = (1/2)y.
Using the substituion method, we replace x with (1/2)y in Eq 1.
Thus, (1/2)y + y = 10
==> (3/2)y = 10
==> y = 20/3
We now know the value of y, so we can find x: x = (1/2)y = (1/2)*(20/3)= 10/3!
You could also use the Gaussian elimination method. But the substitution method is the fastest here . . . for me, at least!
Simple, eh! Hehehe!
Ugh! My usual typos!