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A physicist walks into a bar....

Trygve

Golden Member
Aug 1, 2001
1,428
9
0
Every Friday afternoon, a physicist goes down to the bar, sits in the second-to-last seat, turns to the last seat, which is empty, and asks a girl who isn't there if he can buy her a drink.

The bartender, who is used to weird university types, always shrugs but keeps quiet. But when Valentine's Day arrives, and the physicist makes a particularly heart-wrenching plea into empty space, curiosity gets the better of the bartender, and he says, "I apologize for my stupid questions, but surely you know there is NEVER a woman sitting in that last stool. Why do you persist in asking out empty space?"

The physicist replies, "Well, according to quantum physics, empty space is never truly empty. Virtual particles come into existence and vanish all the time. You never know when the proper wave function will collapse and a girl might suddenly appear there."

The bartender raises his eyebrows. "Really? Interesting. But couldn't you just ask one of the girls who comes here every Friday if you could buy HER a drink? Never know --she might say yes."

The physicist laughs. "Yeah, right -- how likely is THAT to happen?"
 

ItTheCow

Senior member
Apr 7, 2002
365
0
0
Haha, excellent. Here's another science joke that others may enjoy:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"
 

cavemanmoron

Lifer
Mar 13, 2001
13,664
28
91
Originally posted by: ItTheCow
Haha, excellent. Here's another science joke that others may enjoy:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"

:confused:
Huh/./?????
 

Mo0o

Lifer
Jul 31, 2001
24,227
3
76
Originally posted by: cavemanmoron
Originally posted by: ItTheCow
Haha, excellent. Here's another science joke that others may enjoy:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"

:confused:
Huh/./?????

is it bad that i understood that
 

YOyoYOhowsDAjello

Moderator<br>A/V & Home Theater<br>Elite member
Aug 6, 2001
31,205
45
91
Originally posted by: ItTheCow
Haha, excellent. Here's another science joke that others may enjoy:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"

:)
 

Eeezee

Diamond Member
Jul 23, 2005
9,922
0
76
Originally posted by: cavemanmoron
Originally posted by: ItTheCow
Haha, excellent. Here's another science joke that others may enjoy:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"

:confused:
Huh/./?????

The function is e^x. It's treated as a constant if you differentiate with respect to y =p

If you differentiate e^x with respect to x, you get e^x again. You can differentiate a million times with respect to x (what most math students would expect), and you'll still have e^x. But if you differentiate with respect to any other variable, such as y, e^x goes to zero.
 

david46675

Senior member
Jun 9, 2005
404
0
0
Originally posted by: Mo0o
Originally posted by: cavemanmoron
Originally posted by: ItTheCow
Haha, excellent. Here's another science joke that others may enjoy:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"

:confused:
Huh/./?????

is it bad that i understood that

LOL i love it
 

MetalMat

Diamond Member
Jun 14, 2004
9,687
36
91
I did not find it very funny, but then again my sense of humor is retarted.
 
Aug 25, 2004
11,151
1
81
Originally posted by: ItTheCow
Haha, excellent. Here's another science joke that others may enjoy:

A constant function and e^x are walking on Broadway. Then suddenly the constant function sees a differential operator approaching and runs away. So e^x follows him and asks why the hurry. "Well, you see, there's this differential operator coming this way, and when we meet, he'll differentiate me and nothing will be left of me...!" "Ah," says e^x, "he won't bother ME, I'm e to the x!" and he walks on. Of course he meets the differential operator after a short distance.
e^x: "Hi, I'm e^x"
diff.op.: "Hi, I'm d/dy"

I actually laughed out loud at that :(