4x + 30y = whaaaaaaaaaaa?

[BigJ]

Originally posted by: Rogue
Solve for either x or y and then plug the answer back in for the appropriate variable.

All you accomplish by that is going in a circle.

 

[paulney]

You can't solve a linear equation with 2 variables algebraically. You need a system of 2 equations.

 

[amoeba]

whoever is suggesting substitution has not tried it.

 

[Rogue]

Originally posted by: BigJ

Originally posted by: Rogue
Solve for either x or y and then plug the answer back in for the appropriate variable.

All you accomplish by that is going in a circle.

You're absolutely right. It's been a while since I did algebra. Yes, 17.7 does in fact equal 17.7.

 

[HonkeyDonk]

Originally posted by: Rogue

Originally posted by: BigJ

Originally posted by: Rogue
Solve for either x or y and then plug the answer back in for the appropriate variable.

All you accomplish by that is going in a circle.

You're absolutely right. It's been a while since I did algebra. Yes, 17.7 does in fact equal 17.7.

LOL noob

 

[Rogue]

Originally posted by: HonkeyDonk

Originally posted by: Rogue

Originally posted by: BigJ

Originally posted by: Rogue
Solve for either x or y and then plug the answer back in for the appropriate variable.

All you accomplish by that is going in a circle.

You're absolutely right. It's been a while since I did algebra. Yes, 17.7 does in fact equal 17.7.

LOL noob

Not quite. More like old. 10 year high school reunion was last summer. Been a long time for stuff like this....

 

[alm4rr]

Originally posted by: BigJ

Originally posted by: Rogue
Solve for either x or y and then plug the answer back in for the appropriate variable.

All you accomplish by that is going in a circle.

Yea, that is what I tried and I kept going in circles

Thx for the verification

 

[HomeBrewerDude]

easy.


x = 1
y = .9999R

 

[Kadarin]

The correct answer is to multiply both sides of the equation by zero.

(Actually, as others have said, it's a linear equation, which means that on a graph, it would plot as a line with some slope. There is no "solution", since there is no set value for x or y, and no other linear equation with which to find the intersection to give exact values for x and y.)