49^x= 343

[ArJuN]

Originally posted by: StrangerGuy
At first glance x must be greater than 1 and less than 2.

EDIT:

49^x = 343
7^(2x) = 7^3
2x = 3
x = 1.5

QFT
That's the proper way to do it.

 

[Udel]

Originally posted by: bonkers325
49^x = 343

log(49)^x = log(343)

xlog(49)=log(343)

x=log(343)/log(49)

x=1.5

:thumbsup:

 

[Special K]

Originally posted by: Udel

Originally posted by: bonkers325
49^x = 343

log(49)^x = log(343)

xlog(49)=log(343)

x=log(343)/log(49)

x=1.5

:thumbsup:

EDIT: n/m I see it

 

[StevenYoo]

Originally posted by: Udel

Originally posted by: bonkers325
49^x = 343

log(49)^x = log(343)

xlog(49)=log(343)

x=log(343)/log(49)

x=1.5

:thumbsup:

yep, that's how i did it