Yet another, quick math help.

[RESmonkey]

"The rate of water flow R(t) can be approximated by Q(t) = (1/79) (768 + 23t - t^2). Use Q(t) to approximate the average rate of water flow during the 24 hour period.

I am given a data list of certain t values and R(t) values that correspond with the t values.



Just making sure: First, I find the derivative of Q(t), Q'(t).
Then, I do --> fInt[ Q'(t), x, 0, 24]
Divide that by 24, and I should get the average rate of water flow in the 24 hour period, right?

Thanks, again. And I know, this is my third time asking for math help

 

[RESmonkey]

EDIT = I don't think I have to find Q'(t). That gives a funky answer. I tried fnInt with just Q'(t) and got a good logical answer.

Thanks anyways, figured it out...