YAMT: Round 2

AStar617

Diamond Member
Sep 29, 2002
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Can someone give me a start on how to go about approaching a problem like:

Find all real numbers x and y such that 2x+1+3yi = x + 5i

Don't need the answer, just the overall concept, or first step so I can tackle it...

Thx
 

zanieladie

Diamond Member
Jan 19, 2003
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I'm bookmarking this for later. It's 2:30 in the morning here and I'm approaching being brain dead.
 

AStar617

Diamond Member
Sep 29, 2002
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I'm east coast too. Assignment will be handed in by the time "later" rolls around, most likely :p
 

AStar617

Diamond Member
Sep 29, 2002
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Here's what I have so far...

I'm thinking that the y term needs to be alone on one side of the equation... so in this example:

2x+1+3yi = x + 5i

3yi = x + 5i - 2x - 1

3yi = -x + 5i - 1

y = (-x +5i - 1) / 3i

...and this is where it falls apart. I just feel like I'm freewheeling down the wrong path, or should have it in some other form... :confused:

 
Dec 10, 2005
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Wouldn't you want to make y = 0 so you can find the roots of the equation? (almost 3 here, so don't hold me accountable if it doesn't work)
 

AStar617

Diamond Member
Sep 29, 2002
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What i needed to do is set the real and imaginary portions equal to each other, then solve for x and y accordingly.

Yay me :)