Suppose x = (1, 2) and y = (2, 1). We have that:
T( (1, 2) + (2, 1) ) = T( (3, 3) ) = (3 + 1, 3) = (4, 3)
But:
T( (1, 2) ) = (2, 2)
and:
T( (2, 1) ) = (3, 1)
Which gives T( (1, 2) ) + T( (2, 1) ) = (2, 2) + (3, 1) = (5, 3).
Hence T( (1, 2) + (2, 1) ) != T( (1, 2) ) + T( (1, 2) ), so it's not linear.
It fails the second condition too
