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YAMT: complex numbers question

AStar617

Diamond Member
All the examples I see of complex number multiplication always already have the mutliplier/multiplicand in terms of "i", with no sqrts... I'm drawing a blank on how to make the transition...

For instance, what would I do with something like (1 - sqrt[-4])(2 + sqrt[-4]) ?

Thx in advance...
 
thx.... i realize i probably should have used a slightly different example because 4 is too easily sqrt'ed. This modified version of the first example would help me better...

(1 - sqrt[-5])(2 + sqrt[-5])
 
Originally posted by: AStar617
thx.... i realize i probably should have used a slightly different example because 4 is too easily sqrt'ed. This modified version of the first example would help me better...

(1 - sqrt[-5])(2 + sqrt[-5])

Same type of deal:

sqrt(-5) = sqrt(-1)*sqrt(5) = i*sqrt(5)
 
Originally posted by: AStar617
thx.... i realize i probably should have used a slightly different example because 4 is too easily sqrt'ed. This modified version of the first example would help me better...

(1 - sqrt[-5])(2 + sqrt[-5])

turn the sprt(-5) into sqrt (-1) * sqrt (5), or i * sqrt (5).

So when you multiply it out, you get 2 - i*sqrt(5) - sqrt(25)*i^2. i^2 = -1, so the problem ends up being 2 - i*sqrt(5) + 5, or 7 - i*sqrt(5) .
 
Originally posted by: CheesePoofs
Originally posted by: AStar617
thx.... i realize i probably should have used a slightly different example because 4 is too easily sqrt'ed. This modified version of the first example would help me better...

(1 - sqrt[-5])(2 + sqrt[-5])

turn the sprt(-5) into sqrt (-1) * sqrt (5), or i * sqrt (5).

So when you multiply it out, you get 2 - i*sqrt(5) - sqrt(25)*i^2. i^2 = -1, so the problem ends up being 2 - i*sqrt(5) + 5, or 7 - i*sqrt(5) .

OK I think I now know where I'm getting lost... in the sign changes. 😕 Would you mind showing the four products without skipping right to 2 - i*sqrt(5) - sqrt(25)*i^2? Something in the middle (the "b" term of the resulting standard quadratic) is getting simplified there.

EDIT: NM, I think I got it. Thanks alot guys.
 
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