YAMT: Calculus Problem

[speg]

Find the equation(s) of the line(s) through the orgin that are tangent ot the graph of y = (x-1)^3.

Im stumped, I know the line goes through (0,0). And I find y'=3(x-1)^2.

I tried to put 3(x-1)^2 into the equation of a line y-y1 = m ( x -x1) with y' = m, and y1,x1 = 0. but to no avail.

 

[Hyudra]

did you use the equation as f'(x) as h approaches 0 = (f(x+h)-f(x))/h, so you get the slope of the tangent line?, then you use the point-slope form and use 0,0 for the points and you should get the equation of the tangent line.

 

[onza]

dy/dx

ya i'm no help took up to calc2

 

[bootymac]

slope = rise/run!!

Originally posted by: onza
ya i'm no help took up to calc2

Me neither, stupid public school and 40 year old maht 9 text books

 

[Hyudra]

I just did this stuff, its calc 1, lol

 

[agnitrate]

Originally posted by: Hyudra
I just did this stuff, its calc 1, lol

Yeah, this is the most basic of the basic. I think he has the solution since he hasn't posted about it again. Especially since you gave him the answer pretty much.

-silver