YACalculusT: How do you use u*du properly in this integral...

Ricemarine

Lifer
Sep 10, 2004
10,507
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***In this case, since that limit sign is just a big squiggle, i'll use S as the squiggle

limit from -2 to 2 (3u+1)^2 du.
So, first thing, decide on U
Then solve for du/dx, or in this case for random variables, dn/du
[/quote]dn/du = 3, ----> dn/3 = u*dx[/quote]
Here's where I got lost...
1/3 S u^2 *1/3du ----> 1/3 S (3u+1) * du
I know since U is a new variable, the new limits would be 1 and 7...

But as you can see, I am very very lost as to how to go about this... My mat124 calculus teacher told us to scratch the concept in the book and follow his. But this mat125 teacher tells us to go by the book, so I am having a bit of trouble on to how to use U *du properly.

~Thanks for your help.
 

Fenixgoon

Lifer
Jun 30, 2003
33,350
12,933
136
you could just expand the polynomial and integrate.... (if im reading it right)
 

PhlashFoto

Diamond Member
Jun 21, 2003
3,893
17
81
if you expand the polynomial out and u-sub it then, it then turns into a limit -2 to +2; Integral udu problem.

Dont forget to change your limits if need be. :)
 

Fenixgoon

Lifer
Jun 30, 2003
33,350
12,933
136
Originally posted by: ELopes580
if you expand the polynomial out and u-sub it then, it then turns into a limit -2 to +2; Integral udu problem.

Dont forget to change your limits if need be. :)

why u sub after expanding? i dont see why it's necessary:confused:
 

Ricemarine

Lifer
Sep 10, 2004
10,507
0
0
Originally posted by: ELopes580
if you expand the polynomial out and u-sub it then, it then turns into a limit -2 to +2; Integral udu problem.

Dont forget to change your limits if need be. :)

Hmm, I don't understand why if you u sub it then the limit gets reversed...

But in anycase, fenixgoon was correct that if you expanded the polynomial, and then plugged in the limits from there, it would equal the answer, 52.