Originally posted by: coldpower27
Just wanted to make sure.
Heh, I doubt there is that much unneeded circuitry on the Dual Core K8, if the memory controller was boosted to serve 4 cores instead it would indeed become larger. 50mm2 of the die doesn't need to be duplicated out of 183mm2, I am not going to call you wrong, but I seriously doubt that much of the die is saved. And yes I did factor in the fact that it was a Dual Core K8 which you were talking about.
I really don't think the SSE3 instruction set is really a significant part of the die space. The San Diego core at 114mm2 already had that and Toledo was 199mm2, which is 58% the size of Toledo, so they saved 8% die space from Single to Dual Core, using that as a baseline.
I get about 190mm2 for a Quad Core K8 on the 65nm node or 316mm2 on the 90nm node. Which is mildly higher then what you have.
Well that is pretty obvious that AMD wants to optimize it's production capacity, they want to make as much money as they can, even with Fab 36 online, and the impending transistion of Fab 30 to Fab 38 and Fab 7 of Chartered Semi COnductor, as there is now rumors of the 0.5x multiplier 4000+, 4400+, 4800+ instead of having 2x1MB of cache, with the die size I predicted these cores with only 2x512KB cache now will be around the same level as Allendale. They will still prove to be more expensive in production cost then Allendale, due to the fact that AMD uses DSL SOI and that they are at least 1 layer thicker, but they are more optimal.
Soon is a matter of perspective I guess, Clawhammer came out in September 2003, and the 90nm shrink of that core didn't come till April 2005 for the desktop with San Diego, but like I said a core that intorduced a new architecture tends to be at least 200mm2 or close to it on the AMD side and this is using 200mm wafers, with 300mm wafers a ~300mm2 die size to start wouldn't be surprising. Though AMD does do a cache cut if they find they need more room to compete.
On the Intel side of the fence it varies.
Willamette on 0.18 micron is 217mm2 (Big)
Pentium M on 0.13 micron is 82.8mm2 (Small)
Core 2 Duo on 65nm is 143mm2 (Medium)
Yeah, but I would say we should stick with these die size estimates until more concrete proof comes along that can negate the picture we have seen here, 300mm2 is pretty damn realistic IMO. 65nm Quad Cores will be more expensive to produce relative to even 90nm Dual Cores, it will take hte 45nm process to bring this down to a more reasonable level.
Regarding the optical shrink I would say 60% is fair. Since the 0.13 micron to 0.09 micron shrink should yield a die size of 48% if mathematically perfect, so 58% is 10% larger, 90nm to 65nm is 52% for mathematically perfect, so 60% is fine for that.
No if Intel has 2x4MB and that is around 40% of the die for Core Architecture, then (4x512KB & 2MB) is not going to be that significant on K8L, maybe somewhere in the 30% range. But it will be enough to bring the die size to ~300mm2 or so, with the Quad Core K8L.
EDIT: Spelling, and minor additions.