Wondering if somebody can solve an equation for me

[Howard]

sin (theta) - sin (theta) = 0.0002
------------
cos (theta)

What would theta be (in degrees)?

 

[CrackRabbit]

42

 

[Random Variable]

sin(theta)/cos(theta) is tan(theta), you know

 

[Howard]

Originally posted by: Random Variable
sin(theta)/cos(theta) is tan(theta), you know

Yes, I know. Would that make it any easier to solve?

 

[Goosemaster]

~

 

[Random Variable]

there's many solutions

 

[statik213]

I asked mathematica:
to Solve[Sin[thetha]/Cos[thetha] - Sin[thetha] == 0.0002, thetha]
And it gave me:
{{thetha -> -0.036873639289193676`-0.06380931302537549},
{thetha->-0.036873639289193676`-0.06380931302537549},
{thetha->-0.036873639289193676`+0.06380931302537549},
{thetha->-0.036873639289193676`+0.06380931302537549},
{thetha->0.07364727857847068}}

The last one is your answer, it's in radians.

 

[dighn]

graph it

 

[Howard]

Originally posted by: statik213
I asked mathematica:
to Solve[Sin[thetha]/Cos[thetha] - Sin[thetha] == 0.0002, thetha]
And it gave me:
{{thetha -> -0.036873639289193676`-0.06380931302537549},
{thetha->-0.036873639289193676`-0.06380931302537549},
{thetha->-0.036873639289193676`+0.06380931302537549},
{thetha->-0.036873639289193676`+0.06380931302537549},
{thetha->0.07364727857847068}}

The last one is your answer, it's in radians.

Exactly what I was looking for. Thanks!

 

[Random Variable]

4.21967824 degrees

 

[Goosemaster]

I got as far as sin(1-cos(theata))=.0002 but am too sleepy

 

[Goosemaster]

Originally posted by: Howard

Originally posted by: statik213
I asked mathematica:
to Solve[Sin[thetha]/Cos[thetha] - Sin[thetha] == 0.0002, thetha]
And it gave me:
{{thetha -> -0.036873639289193676`-0.06380931302537549},
{thetha->-0.036873639289193676`-0.06380931302537549},
{thetha->-0.036873639289193676`+0.06380931302537549},
{thetha->-0.036873639289193676`+0.06380931302537549},
{thetha->0.07364727857847068}}

The last one is your answer, it's in radians.

Exactly what I was looking for. Thanks!

really? lol

 

[statik213]

Originally posted by: statik213
I asked mathematica:
to Solve[Sin[thetha]/Cos[thetha] - Sin[thetha] == 0.0002, thetha]
And it gave me:
{{thetha -> -0.036873639289193676`-0.06380931302537549},
{thetha->-0.036873639289193676`-0.06380931302537549},
{thetha->-0.036873639289193676`+0.06380931302537549},
{thetha->-0.036873639289193676`+0.06380931302537549},
{thetha->0.07364727857847068}}

The last one is your answer, it's in radians.

oops: copy paste error, the first 4 are imaginary numbers!

 

[statik213]

Originally posted by: Goosemaster
I got as far as sin(1-cos(theata))=.0002 but am too sleepy

how'd you get that?

 

[Goosemaster]

Originally posted by: statik213

Originally posted by: Goosemaster
I got as far as sin(1-cos(theata))=.0002 but am too sleepy

how'd you get that?

lol

trig identities fool


edit:


I got as far as sin(1)cos(cos(theata))-cos(1)sin(cos(theata))...


lol

 

[akubi]

Originally posted by: Goosemaster

Originally posted by: statik213

Originally posted by: Goosemaster
I got as far as sin(1-cos(theata))=.0002 but am too sleepy

how'd you get that?

lol

trig identities fool

that's a joke right? :laugh:

 

[statik213]

Originally posted by: Goosemaster

Originally posted by: statik213

Originally posted by: Goosemaster
I got as far as sin(1-cos(theata))=.0002 but am too sleepy

how'd you get that?

lol

trig identities fool

new skool trig then?