Why do these calc problems pwn me so much?

duragezic

Lifer
Oct 11, 1999
11,234
4
81
Wha, we started a new chapter in my HS calc class and it has questions like:
"A rectangular box with a square base and no top has a total area of 120 cm^2, what dimensions would give it maximum volume?"

And that is probably the easiest kind. Most are a lot more involved and I have no clue on how to even do that one.
They all seem pretty easy since it usually involves algebra like substitution and solving, then take the derivative, but I can NEVER think of what to do. Like when the teacher goes over it it all seems so easy but I just don't think that way like I read a problem and have NO idea where to start it from.
 

GroundZero

Diamond Member
Oct 17, 2002
3,669
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probably because you are a tard
and if you spell owned with a p you will never get variables
 

Gibson486

Lifer
Aug 9, 2000
18,378
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This is almost a related rate porblem, but it really is not calc. I take it that you are trying to solve via derivative?
 

phatj

Golden Member
Mar 21, 2003
1,837
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Wait until you get to Infinite series.. Taylor Series pwned me
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Im currently takin AB calculus.. infinite series arent all that hard... :confused: Taylor series part of the C topic?
 

oboeguy

Diamond Member
Dec 7, 1999
3,907
0
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Don't be afraid of this kind of problem. I used to suck at them and now I'm almost done with a PhD in the stuff. It can be done! :)
 

TuxDave

Lifer
Oct 8, 2002
10,571
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Originally posted by: oboeguy
Don't be afraid of this kind of problem. I used to suck at them and now I'm almost done with a PhD in the stuff. It can be done! :)

*bows down to the Ph'D* (me being a mere M.S. student)
 

phatj

Golden Member
Mar 21, 2003
1,837
0
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Originally posted by: Rkonster
Originally posted by: phatj
Wait until you get to Infinite series.. Taylor Series pwned me

Im currently takin AB calculus.. infinite series arent all that hard... :confused:

Umm, they don't teach Taylor series's and such in Calc AB.


I never said Taylor series were taught in AB. I said infinite series arent all that hard, and infinite series are taught in AB
 

jmcoreymv

Diamond Member
Oct 9, 1999
4,264
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Just had a test on taylor series in my calc bc class. Wasnt too bad once you go over the material enough times.
 

RaynorWolfcastle

Diamond Member
Feb 8, 2001
8,968
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Originally posted by: jmcoreymv
Just had a test on taylor series in my calc bc class. Wasnt too bad once you go over the material enough times.

Taylor series are a piece of cake, I don't know what the big deal is... if you know how to derive, and understand how limits work, you shouldn't have a problem. Incidentally, Taylor series are a subset of the Laurent series which converges everywhere, even where Taylor series diverge. And if you guys think that high school calc is tough, wait till you get to university, a good time will be had by all ;)
 

Syringer

Lifer
Aug 2, 2001
19,333
2
71
Polar Coords were the worst. I never really learned how to find their intersection points and all.

I'm in multivariable calc now and that still stands to be the hardest thing I've heard to learn..which I use loosely.
 

MisterNi

Senior member
Aug 2, 2001
621
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The key to solving calculus problems is to have a clear picture of the problem before attempting it, I'll solve the problem given to start you off. Also note I haven't done calculus for a few years so if anyone sees a mistake, please correct me.

The problem states the surface area of the open ended box is 120cm^2 so we get our initial equation:

4xy (area of the sides of the box) + x^2 (area of the base of the box) = 120cm^2

now we need an equation for the Volume since that's what we're going to be maximizing (I believe this is considered an optimization, max/min problem)

Volume = yx^2 (Volume is height x base)

at this time, I don't believe you've learned how to deal with multi-variable differentials so you'll need to convert V into a single variable equation, so going back to our original equation:

4xy + x^2 = 120cm^2

solving for y gives you:
y = (120 - x^2)/4x

now plug y into our Volume equation:

=> V = (120x^2 - x^4)/4x

now that we have V in terms of x, we find what x needs to be to produce a maximum, but on an exam, you'll want to make sure you put limits on x since we're working with a variable that exists in space

so V = (120x^2 - x^4)/4x where 0< x <infinity

now we differentiate V to find our maximum value of x:

dV/dx = 30 - (3/4)x^2
=>x^2 = 40
x = 6.3246 (looks ok since x falls within 0<x<infinity)

now that we have x, we need to find y so we plug the value x we just found into our original equation:

4(6.2346)y + 40 = 120
y = 3.1423

so the dimensions 6.3246 x 6.3246 x 3.1423 would give the largest possible volume.