A car moving with an initial velocity of 3 mph accelerates at the rate of a(t) = 2.5t mph per second for 7 seconds. How far did it go in those 7 seconds?
A. 0.046 mi
B. 0.047 mi
C. 64.25 mi
D. 0.273 mi
I integrated acceleration, then used the initial velocity to find the velocity equation:
v(t) = 1.25t^2 + 3
I integrated that from 0 to 7, and got 163.92. WTF?
Then, I thoguht, I might have done 7 hours on accident, so I integrated from 0 to (7/60).
I got .351 mi. Again, WTF?
I went back, converted units (hey, maybe they need to be in Miles Per Seconds? ), replacing
3 mph with .05 mps and 2.5t with (1/24)t. Then integrated from 0 to 7.
I got 2.73 mi. That looks like choice D. But why is it not? Typo?
And why didn't I get 2.73 when I did it the second time around ( with integration from 0 to 7/60 )?
I got really pissed, and used an old physics formula, distance = InitialVelocity * time + (1/2)acceleration*timesquared.
Didn't get any of the answer choices, again.
Guidance Appreciated.
Cliffs:
Can't get simple problem.
I posted multiple ways I did it.
A. 0.046 mi
B. 0.047 mi
C. 64.25 mi
D. 0.273 mi
I integrated acceleration, then used the initial velocity to find the velocity equation:
v(t) = 1.25t^2 + 3
I integrated that from 0 to 7, and got 163.92. WTF?
Then, I thoguht, I might have done 7 hours on accident, so I integrated from 0 to (7/60).
I got .351 mi. Again, WTF?
I went back, converted units (hey, maybe they need to be in Miles Per Seconds? ), replacing
3 mph with .05 mps and 2.5t with (1/24)t. Then integrated from 0 to 7.
I got 2.73 mi. That looks like choice D. But why is it not? Typo?
And why didn't I get 2.73 when I did it the second time around ( with integration from 0 to 7/60 )?
I got really pissed, and used an old physics formula, distance = InitialVelocity * time + (1/2)acceleration*timesquared.
Didn't get any of the answer choices, again.
Guidance Appreciated.
Cliffs:
Can't get simple problem.
I posted multiple ways I did it.
