who wants to earn 10 bucks!

Omegachi

Diamond Member
Mar 27, 2001
3,922
0
76
using .net 2003 visual C++

make a grapical program that displays the content of a array(or string) when you click an 'update' button. the way to display the content is with a grid of bitmap. for example, say '1' is a black square and '0' is a white square, if the content of the array is 10100000 then the bitmap will display black sq,white sq, black sq, white, white white...

example

sounds easy right?

i will need your code if you finish the program according to my specs, and i will give your reward via paypal.
 

rmrf

Platinum Member
May 14, 2003
2,872
0
0
yes, you will be learning so much from copying someone's program and handing it in!
 

DaShen

Lifer
Dec 1, 2000
10,710
1
0
$150 and I will consider it. I'll also have it in by the end of the year. :p

Go do your own dang homework!
 

robphelan

Diamond Member
Aug 28, 2003
4,084
17
81
i can do it.. but it'll be in ABAP and you'll need a 150k license for SAP to run it.
 

JoLLyRoGer

Diamond Member
Aug 24, 2000
4,153
4
81
Originally posted by: rmrf
yes, you will be learning so much from copying someone's program and handing it in!

And that's different from most programming anyone does how???:confused:

But others are right...

A) No one's going to write that code from scratch for $10.00
B) Do your own homework..
 

duragezic

Lifer
Oct 11, 1999
11,234
4
81
Dude, if you don't want to do or can't do that program just get out of CS now. I don't know C++ but in Java that would be quite easy.

For loop that goes through the array (from index zero to size-1), then at each position check if it contains 1, then draw black square, else draw white square.
 

DaShen

Lifer
Dec 1, 2000
10,710
1
0
Originally posted by: duragezic
Dude, if you don't want to do or can't do that program just get out of CS now. I don't know C++ but in Java that would be quite easy.

For loop that goes through the array (from index zero to size-1), then at each position check if it contains 1, then draw black square, else draw white square.

QFT