Which is lighter? Moist or dry air? Why?

insdav3

Senior member
Jan 21, 2002
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because water is heavier than air, so when you have a moist head of hair, you head is heavier. Dried hair doesn't have the added weight.

E= mc2
 

minendo

Elite Member
Aug 31, 2001
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Dry air is lighter since moist air is a combination of water vapor and dry air.

Air
 

Atrail

Diamond Member
Apr 20, 2001
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If mosit air was lighter.
Rain would never fall.
rolleye.gif
 

arg

Senior member
Jan 18, 2002
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Does anyone have a scientific answer? Cause my Hydrology prof said moist air is lighter. I got 5 out of 5 wrong on the exam question.
 

jahawkin

Golden Member
Aug 24, 2000
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Moist air is less dense because the molecular weight of water vapor is less than that of other air constituents, such as nitrogen and oxygen.
 

Capn

Platinum Member
Jun 27, 2000
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density of water vapor is less than that of regular air.

Off the top of my head the density of air is about 1.22 kg/m^3, according to this chart you can see water vapor density is a good deal below that.
 

arg

Senior member
Jan 18, 2002
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>Moist air is less dense because the molecular weight of water vapor is less than that of other air constituents, such as nitrogen

b-i-n-g-o
 

Capn

Platinum Member
Jun 27, 2000
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">Moist air is less dense because the molecular weight of water vapor is less than that of other air constituents, such as nitrogen"

I think that justification only works if you assume water vapor is an ideal gas, since we're dealing of temps neat its saturation point it does not behave like an ideal gas afaik.
 

dullard

Elite Member
May 21, 2001
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Do you know the ideal gas law? (Sometimes it is called the perfect gas law.) The ideal gas law states that a given number of gas molecules have a density that only depends only temperature and pressure in a simple manner.

Air behaves very closely like an ideal gas at room temperature and atmospheric pressure. In fact its components also behave like ideal gases (oxygen, nitrogen, water vapor, carbon dioxide, etc...) That means that 1 liter of oxygen has the same number of molecules as 1 liter of nitrogen and 1 liter of water vapor - at the same temperature and pressure. However each water molecule (18 atomic units) is lighter than the oxygen (32 atomic units) and nitrogen molecules (28 atomic units). Thus 1 liter of water vapor weighs less than 1 liter of oxygen or 1 liter of nitrogen.

Thus a given volume of dry air weighs more than the same volume of wet air if they are at the same temperature and pressure.
 

arg

Senior member
Jan 18, 2002
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I think that justification only works if you assume water vapor is an ideal gas

Are you saying that moist air isn't lighter in all cases?
 

jahawkin

Golden Member
Aug 24, 2000
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<<
I think that justification only works if you assume water vapor is an ideal gas, since we're dealing of temps neat its saturation point it does not behave like an ideal gas afaik.
>>



Water vapor being near saturation does nothing to it density. For most practical purposes, atmospheric gases are treated as ideal.
 

dullard

Elite Member
May 21, 2001
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Assuming an ideal gas, dry air is about 61% heavier than an equivalent amount of water vapor.

There are many cases where the ideal gas law fails. Extreme temperatures and extreme pressures are examples.

The ideal gas law also fails when the molecules have attractions toward one another. One oxygen molecule really isn't attracted to another oxygen molecule since they are symmetric and thus have a neutral charge distribution. (Assuming the molecules aren't forced together by the extremes listed above and also ignoring the small Van der Walls forces). Similarly a neutral oxygen molecule isn't attracted to neutral nitrogen or carbon dioxide molecules.

Water is different, it has a dipole (one end is slighly negatively charged and one end is slightly postively charged). Thus if you have lots of water molecules, they will attract one another - leading to a higher density. So when you add more and more water vapor to the air it will become more dense. The key is will it ever reach the 60% more weight needed to surpass the weight of the dry air? Under normal temp and pressure ranges, this 60% increase in density doesn't occur.
 

LiLRiceBoi

Golden Member
Dec 2, 2000
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Doenst temperature have something to do w/ it??

I dont know the answer, just bringing up another idea...
 

CurtisBilly

Senior member
Sep 26, 2000
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Capn is ABSOLUTELY correct. water vapor does not behave like an ideal gas anywhere in the vicinity of the liquid-vapor dome (applicable to most practical and engineering applications). This becomes extremely important when analyzing state changes.

Just for chits and giggles:
the specific volume of pure saturated water vapor @ 1bar 100 degrees C is (from steam tables):
v=1.696 m^3/kg

the specific volume of air @ 1bar 100 degrees C is (from Pv=RuT/molecular weight):
v=1.0704 m^3/kg

Therfore, at this state (and it actually works out at other states as well) that the density of water is less than that of air, so water is "lighter"
 

telstar1

Golden Member
Feb 14, 2001
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Rule of thumb...If you get a question like this on a short quiz, take the less-obvious answer.
 

silverpig

Lifer
Jul 29, 2001
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The answer has been given, but here's a practical observation of the theory.


Weathergirl says "There's a large low pressure system moving into your area" means... RAIN


Weathergirl says "There's a ridge of high pressure sitting right on us" means... SUN
 

SmackdownHotel

Golden Member
May 19, 2000
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Just look at how a barometer works. The barometer level drops when it rains or it's about to rain (less atmospheric pressure), and it rises when the weather is good (increasing atmospheric pressure). That should answer your question.
 

Triumph

Lifer
Oct 9, 1999
15,031
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From my environmental engineering book: "Ironically, although we refer to hot, humid air as 'heavy,' it is in fact less dense than cool, dry air." They go on to prove this through mole fractions, but I don't feel like summarizing it.