- Apr 22, 2005
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Specs are in my sig. All powered by the 450W XClio. About how much more money per month would it cost to power this thing without turning it off than if I only used it for say, 6 hours a day?
Originally posted by: FlyingPenguin
Well it depends on a lot of things. Would you put it in Suspend mode when not using it? That uses a lot less electricity. A modern computer using an LCD draws around 2 - 3 amps under normal use (less when idle and a lot less when in Suspend mode). What does this mean? Well 1 amp is roughly equivalent to a 100 watt light bulb.
So - ballpark figure - under normal use (surfing, playing a game) you're using the equivalent of running three 100 watt light bulbs.
When in suspend mode you're using maybe the equivalent of a 25 watt light bulb? (I'm guessing here - no time to do any calculations). Figure worst case a 50 watt light bulb in suspend mode, but I'll bet it's less than that.
Me, personally, I leave my rig on 24/7 but then again I'm a self-employed IT Tech and I occasionally need to access my PC via Remote Desktop, otherwise I'd let it go into suspend mode when I'm not using it.
Yeah, it's costing me some money, but nothing that will kill me.
If your Dad is like my Dad was (I'm 45 now, so this is no longer an issue) he grumbled about every needless waste of electricity. We got yelled at if we left lights on we didn't need to or sat there staring at the inside of the fridge with the door open for more than a few seconds. God help us if we left a TV set turned on and left the room to take a piss.
Hey don't get me wrong, I'm cheap too, and consider myself eco-friendly, but I need my computers runningtoo, and it's not like a modern computer draws all that much power. Your fridge, AC, and hot water heater are the biggest power eaters in the house.
I have 5 PCs running 24/7 in this house: 2 Media Center PCs, my Wife's workstation and my workstation plus the server.
Originally posted by: t3h l337 n3wb
Specs are in my sig. All powered by the 450W XClio. About how much more money per month would it cost to power this thing without turning it off than if I only used it for say, 6 hours a day?
Originally posted by: antsct
This is very similar to the thread I made before. If you run a server PC without a monitor, keyboard, mouse, speakers etc, does it use much power? Also does Hibernation save more power than Standby?
Thanks.
Originally posted by: ribbon13
Let's assume average of 7 hours per day on a midrange (130w) gaming computer in California for this.
(for my own reference)
1 kWh is equal to 3.6 MJ, or 3.6 x 10^6 J
1 W = 1 J/s
Once we calculate kilowatt hours used per day, it's trivial to work out the annual power consumption.
Ignoring peripherals->
Basis assumption1: Computer drawing 130W @ 68%eff (191W) / 7Hrs/day
Basis assumption2: Computer drawing 130W @ 84%eff (155W) / 7Hrs/day
watts * seconds * minutes * hours == joules
1. ( 191*60*60*7) = 4813200J
2. ( 155*60*60*7) = 3906000J
1 KWh is 3600000J
1. ( 4813200 / 3600000 ) = 1.337KWh
2. ( 3906000 / 3600000 ) = 1.085KWh
According to the EIA the average price per KWh in California is 12.93c
12.93 * 1.337 = 17.28741c per day / $63.10 per year
12.93 * 1.085 = 14.02905c per day / $51.21 per year.
With the Seasonic saving $11.89 per year, over its rated lifetime (MTFB 100k hrs) it will save him $135.73 over the FSP. Paid for itself.
Originally posted by: ribbon13
Example:
Originally posted by: ribbon13
Let's assume average of 7 hours per day on a midrange (130w) gaming computer in California for this.
(for my own reference)
1 kWh is equal to 3.6 MJ, or 3.6 x 10^6 J
1 W = 1 J/s
Once we calculate kilowatt hours used per day, it's trivial to work out the annual power consumption.
Ignoring peripherals->
Basis assumption1: Computer drawing 130W @ 68%eff (191W) / 7Hrs/day
Basis assumption2: Computer drawing 130W @ 84%eff (155W) / 7Hrs/day
watts * seconds * minutes * hours == joules
1. ( 191*60*60*7) = 4813200J
2. ( 155*60*60*7) = 3906000J
1 KWh is 3600000J
1. ( 4813200 / 3600000 ) = 1.337KWh
2. ( 3906000 / 3600000 ) = 1.085KWh
According to the EIA the average price per KWh in California is 12.93c
12.93 * 1.337 = 17.28741c per day / $63.10 per year
12.93 * 1.085 = 14.02905c per day / $51.21 per year.
With the Seasonic saving $11.89 per year, over its rated lifetime (MTFB 100k hrs) it will save him $135.73 over the FSP. Paid for itself.
Need to know exactly how much your system draws and where you live for an accurate measurement.
Originally posted by: Bobthelost
Ok, you have a computer that runs 24/7 365 days a year, it uses on average 200W.
= 4.8 Kwh a day.
= 1752 Kwh a year.
If you're paying around $0.10 per kwh that means you're paying $175 to run it all year long.
However the average power draw from your computer will be less than that. http://www.silentpcreview.com/article265-page4.html The highest load they could get was only 225W, if you're not throwing in huge numbers of Hard drives and running your SLI setup at full load 24/7 then the machine will idle under 100W somewhere. This won't increase much for office apps...