What is the "medium" of this maths question?

[nLinked]

What would the "median" be from the following table?

Weight (kg) Frequency
36<w<40 ---------- 5
41<w<45 ---------- 2
46<w<50 ---------- 4
51<w<55 ---------- 3
56<w<60 ---------- 20
61<w<65 ---------- 4
66<w<70 ---------- 7
71<w<75 ---------- 3
76<w<80 ---------- 1
81<w<85 ---------- 1

 

[yankeesfan]

56<w<60

my guess

 

[HeroOfPellinor]

Originally posted by: yankeesfan
edit: wait..medium?

not median?

Yeah, that's where seven ate nine and then five talked to it from beyond the grave.

 

[Turin39789]

Originally posted by: HeroOfPellinor

Originally posted by: yankeesfan
edit: wait..medium?

not median?

Yeah, that's where seven ate nine and then five talked to it from beyond the grave.

I was taught median as well

"In probability theory and statistics, a median is a number dividing the higher half of a sample, a population, or a probability distribution from the lower half. The median of a finite list of numbers can be found by arranging all the observations from lowest value to highest value and picking the middle one. If there are an even number of observations, one often takes the mean of the two middle values."

So on that list, its the mean,or average, of these two lines

56<w<60 ---------- 20
61<w<65 ---------- 4