Except that doesn't tell the whole story. In fact, there were at least a dozen tiebreakers and "Sen. Sanders won at least a handful," an Iowa Democratic Party official told NPR.
Gone unmentioned so far is that even if Clinton won that Miracle Six and there were no other coin tosses it would make little difference in the outcome. That is, in part, because of the complicated way Iowa Democrats allocate their delegates and what was being reported on election night and what wasn't.
Let's step back and explain that for a second; and this is tricky, so stay with us.
First, understand that the state party reported a grand total of 171,508 caucusgoers, the second-highest turnout in Iowa caucus history behind 2008. And no raw vote was or is ever broken out by candidate and recorded at the Democratic caucuses.
That's because in Iowa, it's a delegate game.
Iowa has a multistep process for picking delegates. Monday night was just Step 1. Here's how it works:
1. There were 1,683 precinct caucuses on Iowa caucus night.
2. Those precinct caucuses elected 11,065 delegates to the county conventions, which take place March 12.
3. That universe of 11,065 delegates is whittled down to 1,406 who will attend congressional district (April 30) and state conventions (June 18).
4. And here's the root of what's causing all the confusion: The breakdown of those 11,065 is not reported on caucus night.
5. What IS reported, what Clinton's 49.9 to 49.6 percent tracing-paper-thin lead is based on, is "state delegate equivalents."
6. Those are ESTIMATES of how many of those 11,065 will attend the congressional district and state conventions.
So ... when those coin tosses are happening, they are elected delegates in that larger universe.
That means, for Clinton to have picked up the four delegates, she would have had to have won not six in a row, but more like 47.