Trying to wire up a boolean function circuit or something...

[JohnCU]

F = B'D' + A'B'C + ABC + CD'

THe function calls for two 3-input AND gates and one 4-input OR gate. All you have available, however, are 2-input AND and OR gates, thus you must discover how to make:

* a 3-input AND from two 2-input AND's and,
* a 4-input OR from three 2-input OR's.

I don't really understand how to manipulate boolean functions very well yet. If anyone could point me in the right direction, I would appreciate it.

 

[amdskip]

I'd try helping you but I learned nothing in this class semester at all. I had a friend do my one and only homework for a 6 pack of budlight🙂

I kinda know what gates are, is this supposed to be assembly programming?

 

[JohnCU]

Originally posted by: amdskip
I'd try helping you but I learned nothing in this class semester at all. I had a friend do my one and only homework for a 6 pack of budlight🙂

I kinda know what gates are, is this supposed to be assembly programming?

I'm using TTL ICs and a little breadboard and wires to hook all these up.

 

[dighn]

gates are basic building blocks in a digital circuit. they are circuit elements.

as for the original question, you can try to reduce it by karnaut (sp) map or something, or just wire it directly

to make 3 input and from 2 input ands, simply connect one output of an and to the input of another and, now you have 3 input and

4 input or from 2 input ors: i'll call the gates A, B C, connect output of A to one input of C, output of B to the othe rinput of C, now you have 4 input or

 

[JohnCU]

Originally posted by: dighn
gates are basic building blocks in a digital circuit. they are circuit elements.

as for the original question, you can try to reduce it by karnaut (sp) map or something, or just wire it directly

to make 3 input and from 2 input ands, simply connect one output of an and to the input of another and, now you have 3 input and

4 input or from 2 input ors: i'll call the gates A, B C, connect output of A to one input of C, output of B to the othe rinput of C, now you have 4 input or

Awesome, thank you.

 

[sandmanwake]

Sounds like you're in ECE 201.

 

[TheLonelyPhoenix]

ABC = (AB)C
in other words, you can attach the output of AB to the imput of another AND gate, and put C on the second input of that gate.

ABCD = (A+B)+(C+D)
use an OR gate on AB and CD seperately. Run the two outputs together through a 3rd OR gate. That's it.

The first thing you come to be familiar with about boolean logic and digital circuits in general is that nothing is greater than the sum of its parts. if you know what output you get for any given set of inputs, you've figured out your circuit. Everything else is just an arrangement of the three basic gates (AND, OR, and NOT)

 

[JohnCU]

Originally posted by: sandmanwake
Sounds like you're in ECE 201.

Yep, had to miss class last week and am trying to play catch up. It's like trying to learn a different language.

 

[EvilYoda]

Wow...guess I don't remember anything from 3 years ago 🙂

Glad someone could help you out though 😛

 

[TuxDave]

Originally posted by: TheLonelyPhoenix
ABC = (AB)C
in other words, you can attach the output of AB to the imput of another AND gate, and put C on the second input of that gate.

A+B+C+D = (A+B)+(C+D)
use an OR gate on AB and CD seperately. Run the two outputs together through a 3rd OR gate. That's it.

The first thing you come to be familiar with about boolean logic and digital circuits in general is that nothing is greater than the sum of its parts. if you know what output you get for any given set of inputs, you've figured out your circuit. Everything else is just an arrangement of the three basic gates (AND, OR, and NOT)

Small correction

 

[her209]

F = bewbies!

 

[Evadman]

Originally posted by: her209
F = bewbies!

🙂