Truth or Myth: If you put a giant box around the Eiffel Tower, the air contained...

her209

No Lifer
Oct 11, 2000
56,336
11
0
within the box will weigh more than the Tower itself.

BTW, saw this on a rerun of MythBusters.
 

blinblue

Senior member
Jul 7, 2006
889
0
76
According to http://www.tour-eiffel.fr/teiffel/uk/documentation/structure/page/chiffres.html
The tower weighs about 10000 tons
The height is 324m, the base is 125m x 125m. So a total volume of 324*125*125= 5062500 m^3
The density of air is 1.275 kg/m^3
So the weight is 1.275 kg/m^3 *5062500 m^3 =6.4547×10^6 kg

10000 tons is equal to 1×10^7 kg, which is greater than 6.45×10^6 kg

So the tower itself has a greater mass according to the numbers I have
 

yankeesfan

Diamond Member
Aug 6, 2004
5,922
1
71
Density of air: 1.2 kg/m3
Height of tower: 324m
Base side length: 100m
Weight of air: 100*100*324*1.2= (3,888,000 kg)(9.8)= 38,102,400 N
Weight of Eiffel tower: (10,000,000 kg)(9.8) = 98,000,000 N

Tower, if it is a box.
 

silverpig

Lifer
Jul 29, 2001
27,703
12
81
According to http://www.tour-eiffel.fr/teiffel/uk/documentation/structure/page/chiffres.html
The tower weighs about 10000 tons
The height is 324m, the base is 125m x 125m. So a total volume of 324*125*125= 5062500 m^3
The density of air is 1.275 kg/m^3
So the weight is 1.275 kg/m^3 *5062500 m^3 =6.4547×10^6 kg

10000 tons is equal to 1×10^7 kg, which is greater than 6.45×10^6 kg

So the tower itself has a greater mass according to the numbers I have

Minus the air displaced because of the tower :p
 

Murloc

Diamond Member
Jun 24, 2008
5,382
65
91
false bc air weighs nothing you dummy
there would be no pressure then
*head explodes*

guys your calculations have a flaw: in the box there is the actual tower too, and it occupies a volume. This just helps the "tower has bigger mass" side anyway.
 

Evadman

Administrator Emeritus<br>Elite Member
Feb 18, 2001
30,990
5
81
BTW, saw this on a rerun of MythBusters.

Then the mythbusters are wrong. It happens sometimes, but they get folks thinking using the scientific method, so kudos to them.
 

DrPizza

Administrator Elite Member Goat Whisperer
Mar 5, 2001
49,601
167
111
www.slatebrookfarm.com
According to http://www.tour-eiffel.fr/teiffel/uk/documentation/structure/page/chiffres.html
The tower weighs about 10000 tons
The height is 324m, the base is 125m x 125m. So a total volume of 324*125*125= 5062500 m^3
The density of air is 1.275 kg/m^3
So the weight is 1.275 kg/m^3 *5062500 m^3 =6.4547×10^6 kg

10000 tons is equal to 1×10^7 kg, which is greater than 6.45×10^6 kg

So the tower itself has a greater mass according to the numbers I have

I think the volume of air is supposed to be the volume of the cylinder that would hold it, not the volume of a box. The area of a circle is pi/2 times bigger than the square it circumscribes. (easy to figure this out.) So, without going through all of the calculations, the mass of the air would be pi/2 times larger.
This gives a mass of 1.014 x 10^7 kg. Which, alas, is more.

But wait! I'm not looking it up, but if I recall correctly, your density of air is at STP. i.e. the pressure at sea level. Paris is NOT at sea level. And, with a mean annual temperature of about 53 degrees, not at standard temperature either. Furthermore, there's no way that the density of air is the same at the bottom of the tower as it is at the top of the tower. In fact, an altimeter (other than a GPS altimeter) doesn't really measure altitude. It really measures air pressure. At 300 meters (towards the top of the Eiffel tower), the density of air is considerably lower. Well, not considerably, but enough that the 1.014 x 10^7 kg figure is actually going to be BELOW 1.000 x 10^7 kg after doing a fun integration.

A quick calculation shows that even if the base of the tower were at sea level (guesstimate that it's around 200 feet above sea level), the top of the tower is around 1050 feet. At 0 degrees C (standard temperature), at the top of the tower, the density of air would be 96.26% of the density it is at the base. If we found the average density, by averaging the density at the bottom with the top (I'm in a hurry at the moment), then the average density of the air would be 98.1% that at STP. 98.1% of that 1.014 x 10^7kg works out to:

.994 x 10^7 kilograms. CLOSE, but no cigar.

In summary: nonsense. At STP, the calculation says yes for a cylinder. But, that completely ignores that the density of air varies with altitude, that the average annual temperature in Paris is in the low 50's (F), the elevation of Paris is above sea level, and that the density of air at the top of the cylinder is less than the density of air at the bottom of the cylinder.

That was fun. :)
 

freejumps

Banned
Nov 7, 2007
105
0
0
I think the volume of air is supposed to be the volume of the cylinder that would hold it, not the volume of a box. The area of a circle is pi/2 times bigger than the square it circumscribes. (easy to figure this out.) So, without going through all of the calculations, the mass of the air would be pi/2 times larger.
This gives a mass of 1.014 x 10^7 kg. Which, alas, is more.

But wait! I'm not looking it up, but if I recall correctly, your density of air is at STP. i.e. the pressure at sea level. Paris is NOT at sea level. And, with a mean annual temperature of about 53 degrees, not at standard temperature either. Furthermore, there's no way that the density of air is the same at the bottom of the tower as it is at the top of the tower. In fact, an altimeter (other than a GPS altimeter) doesn't really measure altitude. It really measures air pressure. At 300 meters (towards the top of the Eiffel tower), the density of air is considerably lower. Well, not considerably, but enough that the 1.014 x 10^7 kg figure is actually going to be BELOW 1.000 x 10^7 kg after doing a fun integration.

A quick calculation shows that even if the base of the tower were at sea level (guesstimate that it's around 200 feet above sea level), the top of the tower is around 1050 feet. At 0 degrees C (standard temperature), at the top of the tower, the density of air would be 96.26% of the density it is at the base. If we found the average density, by averaging the density at the bottom with the top (I'm in a hurry at the moment), then the average density of the air would be 98.1% that at STP. 98.1% of that 1.014 x 10^7kg works out to:

.994 x 10^7 kilograms. CLOSE, but no cigar.

In summary: nonsense. At STP, the calculation says yes for a cylinder. But, that completely ignores that the density of air varies with altitude, that the average annual temperature in Paris is in the low 50's (F), the elevation of Paris is above sea level, and that the density of air at the top of the cylinder is less than the density of air at the bottom of the cylinder.

That was fun. :)

you sound like my physics teacher /confused
 

BurnItDwn

Lifer
Oct 10, 1999
26,280
1,787
126
Air has neutral buoyancy, so as long as it's not pressurized any different than the atmosphere, it's weight will be zero, no?

Note: weight = mass times force. if neutral buoyancy then force = 0, thus, no weight.
 

PieIsAwesome

Diamond Member
Feb 11, 2007
4,054
1
0
Air has neutral buoyancy, so as long as it's not pressurized any different than the atmosphere, it's weight will be zero, no?

Note: weight = mass times force. if neutral buoyancy then force = 0, thus, no weight.

The weight is still there, just that there is an equal and opposite force opposing the weight (the "buoyancy" I guess) if the body with weight (in this case a volume of air) is not accelerating up or down.

Maybe to get the exact mass of the air in the invisible box, someone can find the density of the air as a function of height, make a nice little integration, and somehow take into account the space taken up by the tower. D:
 
Feb 24, 2001
14,513
4
81
I think the volume of air is supposed to be the volume of the cylinder that would hold it, not the volume of a box. The area of a circle is pi/2 times bigger than the square it circumscribes. (easy to figure this out.) So, without going through all of the calculations, the mass of the air would be pi/2 times larger.
This gives a mass of 1.014 x 10^7 kg. Which, alas, is more.

But wait! I'm not looking it up, but if I recall correctly, your density of air is at STP. i.e. the pressure at sea level. Paris is NOT at sea level. And, with a mean annual temperature of about 53 degrees, not at standard temperature either. Furthermore, there's no way that the density of air is the same at the bottom of the tower as it is at the top of the tower. In fact, an altimeter (other than a GPS altimeter) doesn't really measure altitude. It really measures air pressure. At 300 meters (towards the top of the Eiffel tower), the density of air is considerably lower. Well, not considerably, but enough that the 1.014 x 10^7 kg figure is actually going to be BELOW 1.000 x 10^7 kg after doing a fun integration.

A quick calculation shows that even if the base of the tower were at sea level (guesstimate that it's around 200 feet above sea level), the top of the tower is around 1050 feet. At 0 degrees C (standard temperature), at the top of the tower, the density of air would be 96.26% of the density it is at the base. If we found the average density, by averaging the density at the bottom with the top (I'm in a hurry at the moment), then the average density of the air would be 98.1% that at STP. 98.1% of that 1.014 x 10^7kg works out to:

.994 x 10^7 kilograms. CLOSE, but no cigar.

In summary: nonsense. At STP, the calculation says yes for a cylinder. But, that completely ignores that the density of air varies with altitude, that the average annual temperature in Paris is in the low 50's (F), the elevation of Paris is above sea level, and that the density of air at the top of the cylinder is less than the density of air at the bottom of the cylinder.

That was fun. :)

Do those figures take into account that the tower displaces less air the further up you go?
 

DrPizza

Administrator Elite Member Goat Whisperer
Mar 5, 2001
49,601
167
111
www.slatebrookfarm.com
Air has neutral buoyancy, so as long as it's not pressurized any different than the atmosphere, it's weight will be zero, no?

Note: weight = mass times force. if neutral buoyancy then force = 0, thus, no weight.


Ahhh! And let's get even more technical, shall we. If we were to stick the Eiffel Tower into the ocean and put a giant bathroom scale under it, we would see that the weight was less. That's because of the buoyant force exerted on the tower. Well, the air actually exerts a buoyant force on the Eiffel tower. So, do they mean a mass of 10^7 kg, or an equivalent weight. And, if they mean an equivalent weight, is that weight measured in a vacuum? Or at STP?

And, in case you doubt that gases exert a buoyant force,
http://www.youtube.com/watch?v=XjCmwuGKR6g
Note the aluminum foil boat floating in sulfur hexafluoride.
 

OutHouse

Lifer
Jun 5, 2000
36,410
616
126
According to http://www.tour-eiffel.fr/teiffel/uk/documentation/structure/page/chiffres.html
The tower weighs about 10000 tons
The height is 324m, the base is 125m x 125m. So a total volume of 324*125*125= 5062500 m^3
The density of air is 1.275 kg/m^3
So the weight is 1.275 kg/m^3 *5062500 m^3 =6.4547×10^6 kg

10000 tons is equal to 1×10^7 kg, which is greater than 6.45×10^6 kg

So the tower itself has a greater mass according to the numbers I have

<<<Twitching
 

MikeMike

Lifer
Feb 6, 2000
45,885
66
91
Do those figures take into account that the tower displaces less air the further up you go?

does it also take into account that the tower is not completely solid, air exists within the columns that are hollow, is there an official "displacement" for the tower?
 

silverpig

Lifer
Jul 29, 2001
27,703
12
81
Ahhh! And let's get even more technical, shall we. If we were to stick the Eiffel Tower into the ocean and put a giant bathroom scale under it, we would see that the weight was less. That's because of the buoyant force exerted on the tower. Well, the air actually exerts a buoyant force on the Eiffel tower. So, do they mean a mass of 10^7 kg, or an equivalent weight. And, if they mean an equivalent weight, is that weight measured in a vacuum? Or at STP?

And, in case you doubt that gases exert a buoyant force,
http://www.youtube.com/watch?v=XjCmwuGKR6g
Note the aluminum foil boat floating in sulfur hexafluoride.

Then there's the archimedes forces...

I distilled it down to mass, and a rectangular box. The only other options that are valid in physics are a spherical box and a cylinder, both being a stretch in this case.
 

zerocool84

Lifer
Nov 11, 2004
36,041
472
126
So have we concluded yes or no? All I see is a bunch of numbers, no definite answer yet.