Originally posted by: Qacer
Find a matrix P that diagonalizes
A =
[0 0 -2]
[1 2 1]
[1 0 3]
Then find the transpose of that matrix.
mmm, linear algebra
ok... L is Lamda
First find all of L
so
det([L 0 2]
[-1 L-2 -1]
[-1 0 L-3])
gives
(L-2)*det([L 2]
[-1 L-3])
= (L-2)(L*(L-3) + 2) = (L-2)(L^2 - 3L + 2) = (L-2)(L-1)(L-2)
= (L=2) and (L=1)
Finding the basis for Nullspace with L = 2
2 0 2 0 gives 1 0 1 0 so x -s -1
-1 0 -1 0 0 0 0 0 y = 0 = 0
-1 0 -1 0 0 0 0 0 z s 1
Finding the basis for Nullspace with L = 1
1 0 2 0 gives 1 0 2 0 so x -2s -2
-1 -1 -1 0 0 1 -1 0 y = s = 1
-1 0 -2 0 0 0 0 0 z s 1
take the basis and form a matrix P... using L=2 L=2 L=1's basis for nullspace
P= -1 -1 -2
0 0 1
1 1 1
PAP^t = D where D = 2 0 0
0 2 0
0 0 1
so
just find P^t... i'll leave that part to you
[-1 -1 -2][0 0 -2][ ] [2 0 0]
[0 0 1][1 2 1][ ] = [0 2 0]
[1 1 1][1 0 3][ ] [0 0 1]
if there are any mistakes... ignore all the above
edit: ugh, formatting came out horrible... to see it correctly, just click "quote" and read it in the message text box