The Help CodeDude study for his math test THREAD *UPDATED NEW QUESTION*

[MrCodeDude]

Originally posted by: 3L33T32003
Yah well, the last time I took an hour out of my life and did something for this guy he did not even send me a thank you note. So from now on he gets flamed when he asks for free help from his "friends" here at atot.

Umm, unless it took you an hour to do some other chemistry or math question I asked, then I have no clue what you're talking about. Unless you're CasioTech, in which case you shouldn't even be here.
-- mrcodedude

 

[MrCodeDude]

Originally posted by: Howard
BTW, why do your math homework on yellow paper?

Hehe, no. I do homework in a notebook, it's just I write bigger on scratch paper so it's more readable.
-- mrcodedude

 

[agnitrate]

Originally posted by: 3L33T32003

Yah well, the last time I took an hour out of my life and did something for this guy he did not even send me a thank you note. So from now on he gets flamed when he asks for free help from his "friends" here at atot.

MrCodeDude has been nothing but thankful in any of the threads I've seen.

My question to you is, what are you going to do when it's 2004?

-silver

 

[MrCodeDude]

Originally posted by: agnitrate
MrCodeDude has been nothing but thankful in any of the threads I've seen.
-silver

I appreciate the support. And this guy should know, god knows how many times he's helped me with Chem 🙂
-- mrcodedude

 

[Shooters]

I don't know if you've figured the problem out yet, but the two lines of the solution that you posted are wrong.

 

[BruinEd03]

Originally posted by: MrCodeDude

Originally posted by: Howard
BTW, why do your math homework on yellow paper?

Hehe, no. I do homework in a notebook, it's just I write bigger on scratch paper so it's more readable.
-- mrcodedude

first of all u are factoring out the cos...so it should be cos(x) * (2*cos(x)-1) what i suggest you doing instead is moving the 1 to the other side first...so you get

2*cos^2(x)-cos(x)-1 = 0 then substitute Y for cos(x) and solve via quadratic equation/factoring and solve for Y. Then equate whatever you get for Y to cos(x).

-Ed

 

[MrCodeDude]

Originally posted by: BruinEd03

Originally posted by: MrCodeDude

Originally posted by: Howard
BTW, why do your math homework on yellow paper?

Hehe, no. I do homework in a notebook, it's just I write bigger on scratch paper so it's more readable.
-- mrcodedude

first of all u are factoring out the cos...so it should be cos(x) * (2*cos(x)-1) what i suggest you doing instead is moving the 1 to the other side first...so you get

2*cos^2(x)-cos(x)-1 = 0 then substitute Y for cos(x) and solve via quadratic equation/factoring and solve for Y. Then equate whatever you get for Y to cos(x).

-Ed

Yeah, thanks. I got the answer by using Quadratic equation. Thanks 🙂 And Shooters, I know my second line is now wrong, but thanks anyway.
-- mrcodedude

 

[Shooters]

Yeah, thanks. I got the answer by using Quadratic equation. Thanks 🙂 And Shooters, I know my second line is now wrong, but thanks anyway.
-- mrcodedude

Good job, I just didn't know if you had realized the error amongst all the petty "do your own homework" comments that others were throwing out.

 

[FelixDeCat]

Yes, I would suggest taking the inverse ratio of 3/4ths divided by the cross tangent of pi, to the power of your typical linear equation. 😕

 

[MrCodeDude]

Originally posted by: FelixDeKat
Yes, I would suggest taking the inverse ratio of 3/4ths divided by the cross tangent of pi, to the power of your typical linear equation. 😕

Come again? 😉 😀
-- mrcodedude

 

[Martin]

Originally posted by: MrCodeDude

Originally posted by: MartyTheManiak
cos x =1
or
cos x = 1/2

There fore
x = 0, pi/3 and others, depeding on what the range is..

That's what I got, but the book says otherwise 🙁
-- mrcodedude

my bad, I am used to seeing a 0 on the RHS.

 

[MrCodeDude]

Bump. New Question 🙂

If you are only planning on saying, "Do your own damn homework." it's already been said.
-- mrcodedude

 

[GoodToGo]

Same thing, Cos(4x) = 2Cos^2(2x) - 1. Substitute Cos(2x) as an independent variable and solve.

 

[MrCodeDude]

Originally posted by: GoodToGo
Same thing, Cos(4x) = 2Cos^2(2x) - 1. Substitute Cos(2x) as an independent variable and solve.

Eh? I don't get it. I'm stupid, hence why I made this thread. 🙂
-- mrcodedude

 

[MrCodeDude]

Bizzity Bump. I'm a stupid HS student.
-- mrcodedude

 

[MrCodeDude]

Originally posted by: MrCodeDude
Bizzity Bump. I'm a stupid HS student.
-- mrcodedude

 

[BruinEd03]

Originally posted by: MrCodeDude

Originally posted by: MrCodeDude
Bizzity Bump. I'm a stupid HS student.
-- mrcodedude

this might help 🙂

-Ed