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the energy of a proton moving at 0.999999991c

Random Variable

Random Variable

Lifer
It's 7 teraelelectronvolts (or 1.12152352 × 10-6 joules), but I can't seem to derive it correctly.

E = [(mc^2)^2 +(pc)^2]^(1/2) = [(mc^2)^2+(mv/((1-v^2/c^2)^(1/2))*c)^2]^(1/2)

where m is the mass of the proton, c is the speed of light, and v is the speed of the proton? Is that right?

This thread of forum continuum has lost its momentum and is hereby stopped. - Moderator Rubycon
 
Originally posted by: Random Variable
It's 7 teraelelectronvolts (or 1.12152352 × 10-6 joules), but I can't seem to derive it correctly.

E = [(mc^2)^2 +(pc)^2]^(1/2) = [(mc^2)^2+(mv/((1-v^2/c^2)^(1/2))*c)^2]^(1/2)

where m is the mass of the proton, c is the speed of light, and v is the speed of the proton? Is that right?
Click to expand...

You forgot to factor in the power derived from the Flux Capacitor and the 1.21 Jigawatts!

😉
 
Originally posted by: Random Variable
It's 7 teraelelectronvolts (or 1.12152352 × 10-6 joules), but I can't seem to derive it correctly.

E = [(mc^2)^2 +(pc)^2]^(1/2) = [(mc^2)^2+(mv/((1-v^2/c^2)^(1/2))*c)^2]^(1/2)

where m is the mass of the hardon, c is the speed of collusion, and v is the speed of the proton? Is that right?
Click to expand...

now it should make more sense
 
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