Texas holdum experts need the answer!

[Finality]

So heres the deal two of us where playing Texas holdum, I had a 6 & Ace, the other had a 6 & 7, cards came down and it was a 3, 4, 5, 7 plus a Queen, both of us where all in.

Who wins? Both of us had straights but I wasn't too sure if there pair of 7's won out or did the Ace beat it?

I assumed the pair of 7's won out but I'm not too sure, anyone care to chime in?

 

[Nomada]

Pretty sure it's the pair.
EDIT-what the guy below said:thumbsup:

 

[PowerMac4Ever]

split pot

 

[sygyzy]

Split Pot.

 

[poncherelli2]

you both have a straight, you split

 

[Rapidskies]

You only use 5 cards to make a hand. As the others pointed out it would be a split pot.

 

[chuckywang]

split pot

 

[RaiderJ]

Split pot unless you rank suits.... but if the shared 7 is of a higher suit then you'd have to split?

If it was my group of friends, it would be a split - fairest way to go.

 

[klah]

quickest draw = teh winnar

 

[tm37]

At that time we use the tie breaker which is longest wang.

 

[MDE]

Split the pot, you both had the same 5 card hand.

 

[Nebben]

As stated above, you split the pot. You can never use more than five cards to make your hand. If both players have the same five-card hand, it does not matter what pairs, kickers, etc are held. the 6th and 7th cards do not exist.