Okay.. I'm trying to figure out how to figure out the final gear ratio on my scooter.
Let's see if I can explain this clearly.
The primary drive sprocket(PD1) has 10 teeth.
The primary driven sprocket(PD2) has 52 teeth.
The secondary drive sprocket(SD1) has 9 teeth
The secondary driven sprocket(SD2) has 20 teeth.
Would the formula be (PD1/PD2)(SD1/SD2)=n?
10/52 = 5.2
9/20 = 2.2222
n= 11.555:1 ?
lol...
Thanks.
Let's see if I can explain this clearly.
The primary drive sprocket(PD1) has 10 teeth.
The primary driven sprocket(PD2) has 52 teeth.
The secondary drive sprocket(SD1) has 9 teeth
The secondary driven sprocket(SD2) has 20 teeth.
Would the formula be (PD1/PD2)(SD1/SD2)=n?
10/52 = 5.2
9/20 = 2.2222
n= 11.555:1 ?
lol...
Thanks.
