sphere equation

Keego

Diamond Member
Aug 15, 2000
6,223
2
81
To find the radius and center of the sphere equation below, you need to first complete the square (or plug in the #'s to your calc) anyways, what's the radius and coords of the center of this sphere equation:

x^2+y^2+z^2+4x-2y-4z

 

Ameesh

Lifer
Apr 3, 2001
23,686
1
0
if you know how to do it, why dont you just do it you need to get it into the form (x+?)^2+(y+?)^2+(z+?)^2
 

MrBond

Diamond Member
Feb 5, 2000
9,911
0
76
You have to complete the square on that equation. Give me a minute and I'll se how rusty I am at doing that :)

Edit: (again) Mental note, don't do simple algebra in head)

:)
 

Atlantean

Diamond Member
May 2, 2001
5,296
1
0
Don't you group the variables?
x(x+4)+y(y-2)+z(z-4)
and then solve? I have no idea how it is actually done though.
 

minendo

Elite Member
Aug 31, 2001
35,560
22
81
(x+2)^2 + (y-1)^2 + (z-2)^2 = 9

I could be wrong in this cause I did just attempt to do it in my head and I am rusty at it.
 

Keego

Diamond Member
Aug 15, 2000
6,223
2
81
Thanks, we just had that in a quiz, glad to know I was right :)