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SOS SOS SOS STATIstics question!

A

amdguy

Banned
Let A B C be the events that John gets job offers from three companies that interviewed him.
Suppose P(A) = P(B) = P(C) = 0.6 and all three events are independent of each other
The probability that john gets at least one job offer is?
 
Isn't this almost the same as an example in your textbook? They have to have something on N independent events.

Not trying to be cruel, but if you can't arrive at the answer yourself now, good luck tryiong to do the similar problems that will be on the midterm and final.

(but like JetBlack69] said, today is opposite day.)
 
well, since it's the probability that he gets AT LEAST ONE job offer, so he can get 1, 2 or 3 job offers so it's the probability of P(one offer) + P(2 offers) + P(3 offers) or 1-P(no offers)
 
Originally posted by: amdguy
How do you calc that??

1-P(He gets no job from all three)
Click to expand...

😕

So in a way, you're given:

P(he doesn't get it from A) = 0.4
P(he doesn't get it from B) = 0.4
P(he doesn't get it from C) = 0.4

So to find the probability of ALL THOSE occuring and since they're independent... you.......

multiply them together and you'll get P(He gets no job from all three)

Edit: Not in a mean way, you should probably get a tutor so you'll get more practice. You'll need to pass the midterms/finals too. Good luck!
 
The fact that they are independent is HUGE becuase P(A)&P(B) = P(A)*P(B)
EDIT: only if they are independent.
 
Originally posted by: JetBlack69
The fact that they are independent is HUGE becuase P(A)&P(B) = P(A)*P(B)
EDIT: only if they are independent.
Click to expand...

Very true.... I'll bold/italicize/underline it in my post above to make it more apparant.
 
i got it!!

there is a formula for 3 events

P( A U B U C ) = P( A ) = P ( B ) + P ( C ) - P( AB ) ? P( AC ) ? P (BC) + P ( ABC )
 
Originally posted by: amdguy
i got it!!

there is a formula for 3 events

P( A U B U C ) = P( A ) = P ( B ) + P ( C ) - P( AB ) ? P( AC ) ? P (BC) + P ( ABC )
Click to expand...

Don't memorize the formulas, learn the ideas. Granted I forgot the ideas in my first few posts. 😱
 
Originally posted by: amdguy
i got it!!

there is a formula for 3 events

P( A U B U C ) = P( A ) = P ( B ) + P ( C ) - P( AB ) ? P( AC ) ? P (BC) + P ( ABC )
Click to expand...

Heh... I bet you a :cookie: that you use the formula incorrectly for the problem. 🙂
 
Originally posted by: amdguy
i got it!!

there is a formula for 3 events

P( A U B U C ) = P( A ) = P ( B ) + P ( C ) - P( AB ) ? P( AC ) ? P (BC) + P ( ABC )
Click to expand...

did you type it wrong? Shouldn't it be P(A) +, not an '='.
 
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