OK
basic biot-savart law question.
I have a current-carrying square, side length L and current I.
The magnetic field magnitude is 4*(4(pi)*10^-7*I)/(4(pi)*(L/2))*(cos(theta1)-cos(theta2)) where theta1 and theta2 are the angles along the axis of the side. I'm going to skip the derivation for that, obviously, but its the same for any line. This is correct.
However, I bend the square into a circular loop.
The magnitude of a circle carrying a current is: (4(pi)*10^-7*I))/(2*R) because you are integrating over 2*pi for the loop. The question is, how do you get the radius from the side L of the square? NO ONE has a clue how to do it on our own physics forums, maybe someone here can help? I set R = sqrt(L^2/pi) but that isn't working, and I'm pretty sure this formula is correct.
basic biot-savart law question.
I have a current-carrying square, side length L and current I.
The magnetic field magnitude is 4*(4(pi)*10^-7*I)/(4(pi)*(L/2))*(cos(theta1)-cos(theta2)) where theta1 and theta2 are the angles along the axis of the side. I'm going to skip the derivation for that, obviously, but its the same for any line. This is correct.
However, I bend the square into a circular loop.
The magnitude of a circle carrying a current is: (4(pi)*10^-7*I))/(2*R) because you are integrating over 2*pi for the loop. The question is, how do you get the radius from the side L of the square? NO ONE has a clue how to do it on our own physics forums, maybe someone here can help? I set R = sqrt(L^2/pi) but that isn't working, and I'm pretty sure this formula is correct.