Someone mind helping me with this math problem?

[Ricemarine]

Ok...

I'm supposed to use reference triangles to find the other angles which are equivalent to cosine ___.....

Ex... Find three other angles that cosine theta = cosine 81...

How do you use reference triangles to find the other 3 angles?...


Btw: I have exhausted all my resources so I got some problem now lol...

 

[DaWhim]

I lost faith in atot, they couldn't do my macroeco problems :brokenheart:

 

[Hyperblaze]

Originally posted by: DaWhim
I lost faith in atot, they couldn't do my macroeco problems :brokenheart:

we have ethics. we don't help you cheat.

 

[dighn]

what is a reference triangle?

 

[KLin]

The answer is 42 degrees fahrenheit.

 

[Heisenberg]

I suppose just adding multiples of 2*Pi to the angle is too simple?

 

[Ricemarine]

Originally posted by: Heisenberg
I suppose just adding multiples of 2*Pi to the angle is too simple?

Mmm yeap....

 

[JustAnAverageGuy]

Originally posted by: dighn
what is a reference triangle?

Good Question.

 

[DaWhim]

Originally posted by: Hyperblaze

Originally posted by: DaWhim
I lost faith in atot, they couldn't do my macroeco problems :brokenheart:

we have ethics. we don't help you cheat.

you sound like an idiot. what made you think I am cheating? :roll:

 

[Ricemarine]

Technically this isn't cheating cause I posted an example...

No its not from the book.

 

[akubi]

the answer is obvious to the most casual observer

 

[Ricemarine]

Originally posted by: akubi
the answer is obvious to the most casual observer

Then mind telling me the answer?!

 

[akubi]

you draw the reference triangle in the first quadrant at 81 and flip it three times in the other three quadrants. obviously, two of them are negative and one is positive.

that's enough hints for you noob

 

[Rubycon]

25 or 6 to 4

height = 27

 

[DrPizza]

hint hint:

If Tony Hawk does a 360, is he facing the same way when he lands?
How about a 720?

 

[ArJuN]

How old are you? This is pre-calc stuff...

 

[Soccer55]

Originally posted by: akubi
you draw the reference triangle in the first quadrant at 81 and flip it three times in the other three quadrants. obviously, two of them are negative and one is positive.

that's enough hints for you noob

Not quite. The ones appearing in the 2nd and 3rd quadrants would be the negative of what he's looking for. DrPizza gave the best hint for solving this problem.

-Tom

 

[akubi]

Originally posted by: Soccer55

Originally posted by: akubi
you draw the reference triangle in the first quadrant at 81 and flip it three times in the other three quadrants. obviously, two of them are negative and one is positive.

that's enough hints for you noob

Not quite. The ones appearing in the 2nd and 3rd quadrants would be the negative of what he's looking for. DrPizza gave the best hint for solving this problem.

-Tom

not quite. he already explained adding/subtracting multiples of 360 is not it.

 

[Chaotic42]

This may be a super-cheap cop out, but can you switch angle systems?

cos 81 radians /= cos 81° /= cos 81'

 

[DrPizza]

Originally posted by: akubi

Originally posted by: Soccer55

Originally posted by: akubi
you draw the reference triangle in the first quadrant at 81 and flip it three times in the other three quadrants. obviously, two of them are negative and one is positive.

that's enough hints for you noob

Not quite. The ones appearing in the 2nd and 3rd quadrants would be the negative of what he's looking for. DrPizza gave the best hint for solving this problem.

-Tom

not quite. he already explained adding/subtracting multiples of 360 is not it.

Actually, Heisenberg suggested doing that in radian measure, not in degrees.
Which seemed to not work for the OP, therefore the OP probably hasn't been exposed to radian measure yet.
Furthermore, for the function y = cos x on the domain 0 < x < 360 degrees, each member of the range -1<x<1 appears exactly twice. There aren't 4 values. Thus, 2 members of the solution must be outside this domain.

 

[DaShen]

Originally posted by: akubi
you draw the reference triangle in the first quadrant at 81 and flip it three times in the other three quadrants. obviously, two of them are negative and one is positive.

that's enough hints for you noob

 

[tami]

ask your teacher.

 

[akubi]

Originally posted by: DrPizza

Originally posted by: akubi

Originally posted by: Soccer55

Originally posted by: akubi
you draw the reference triangle in the first quadrant at 81 and flip it three times in the other three quadrants. obviously, two of them are negative and one is positive.

that's enough hints for you noob

Not quite. The ones appearing in the 2nd and 3rd quadrants would be the negative of what he's looking for. DrPizza gave the best hint for solving this problem.

-Tom

not quite. he already explained adding/subtracting multiples of 360 is not it.

Actually, Heisenberg suggested doing that in radian measure, not in degrees.
Which seemed to not work for the OP, therefore the OP probably hasn't been exposed to radian measure yet.
Furthermore, for the function y = cos x on the domain 0 < x < 360 degrees, each member of the range -1<x<1 appears exactly twice. There aren't 4 values. Thus, 2 members of the solution must be outside this domain.

look, it's not hard to infer what the op is trying to ask.
if he wanted multiples of 360 added to 81 (which would amount to be nothing more than a retarded exercise), he would not have brought up reference angles, nor 3 answers.
the problems is usually phrased such that you use reference angles to obtain equivalent pairs of sines and cosines wrt the four quadrants.

i suggest that the op type out the problem word for word from the book and explicitly declare the domain on theta.