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Someone mind helping me with this math problem?

Ricemarine

Ricemarine

Lifer
Ok...

I'm supposed to use reference triangles to find the other angles which are equivalent to cosine ___.....

Ex... Find three other angles that cosine theta = cosine 81...

How do you use reference triangles to find the other 3 angles?...


Btw: I have exhausted all my resources so I got some problem now lol...
 
you draw the reference triangle in the first quadrant at 81 and flip it three times in the other three quadrants. obviously, two of them are negative and one is positive.

that's enough hints for you noob
 
hint hint:

If Tony Hawk does a 360, is he facing the same way when he lands?
How about a 720?
 
Originally posted by: akubi
you draw the reference triangle in the first quadrant at 81 and flip it three times in the other three quadrants. obviously, two of them are negative and one is positive.

that's enough hints for you noob
Click to expand...

Not quite. The ones appearing in the 2nd and 3rd quadrants would be the negative of what he's looking for. DrPizza gave the best hint for solving this problem.

-Tom
 
Originally posted by: Soccer55
Originally posted by: akubi
you draw the reference triangle in the first quadrant at 81 and flip it three times in the other three quadrants. obviously, two of them are negative and one is positive.

that's enough hints for you noob
Click to expand...

Not quite. The ones appearing in the 2nd and 3rd quadrants would be the negative of what he's looking for. DrPizza gave the best hint for solving this problem.

-Tom
Click to expand...

not quite. he already explained adding/subtracting multiples of 360 is not it.
 
Originally posted by: akubi
Originally posted by: Soccer55
Originally posted by: akubi
you draw the reference triangle in the first quadrant at 81 and flip it three times in the other three quadrants. obviously, two of them are negative and one is positive.

that's enough hints for you noob
Click to expand...

Not quite. The ones appearing in the 2nd and 3rd quadrants would be the negative of what he's looking for. DrPizza gave the best hint for solving this problem.

-Tom
Click to expand...

not quite. he already explained adding/subtracting multiples of 360 is not it.
Click to expand...

Actually, Heisenberg suggested doing that in radian measure, not in degrees.
Which seemed to not work for the OP, therefore the OP probably hasn't been exposed to radian measure yet.
Furthermore, for the function y = cos x on the domain 0 < x < 360 degrees, each member of the range -1<x<1 appears exactly twice. There aren't 4 values. Thus, 2 members of the solution must be outside this domain.
 
Originally posted by: akubi
you draw the reference triangle in the first quadrant at 81 and flip it three times in the other three quadrants. obviously, two of them are negative and one is positive.

that's enough hints for you noob
Click to expand...

 
Originally posted by: DrPizza
Originally posted by: akubi
Originally posted by: Soccer55
Originally posted by: akubi
you draw the reference triangle in the first quadrant at 81 and flip it three times in the other three quadrants. obviously, two of them are negative and one is positive.

that's enough hints for you noob
Click to expand...

Not quite. The ones appearing in the 2nd and 3rd quadrants would be the negative of what he's looking for. DrPizza gave the best hint for solving this problem.

-Tom
Click to expand...

not quite. he already explained adding/subtracting multiples of 360 is not it.
Click to expand...

Actually, Heisenberg suggested doing that in radian measure, not in degrees.
Which seemed to not work for the OP, therefore the OP probably hasn't been exposed to radian measure yet.
Furthermore, for the function y = cos x on the domain 0 < x < 360 degrees, each member of the range -1<x<1 appears exactly twice. There aren't 4 values. Thus, 2 members of the solution must be outside this domain.
Click to expand...

look, it's not hard to infer what the op is trying to ask.
if he wanted multiples of 360 added to 81 (which would amount to be nothing more than a retarded exercise), he would not have brought up reference angles, nor 3 answers.
the problems is usually phrased such that you use reference angles to obtain equivalent pairs of sines and cosines wrt the four quadrants.

i suggest that the op type out the problem word for word from the book and explicitly declare the domain on theta.
 
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