ThunderbirdElitist
Banned
X^2 + Y^2 + Z^2 = 4 ; z = sqrt(x^2+y^2)
I'm assuming sperical coordinates would be the easiest way.
I get x = 2sin(Ro)Cos(theta) ; y=2Sin(ro)Cos(theta) ; z=2Sin(Ro)
But this isn't correct.
I'm assuming sperical coordinates would be the easiest way.
I get x = 2sin(Ro)Cos(theta) ; y=2Sin(ro)Cos(theta) ; z=2Sin(Ro)
But this isn't correct.