- Sep 10, 2004
- 10,507
- 0
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I'm savoring my posts before I reach lifer
...
Anyhow, I have the step function equation
f(t) =
{ 0 , t < pi
{ t - pi , pi <= t < 2pi
{ 0 , t >= 2pi
So I tried plugging it in
L{ (t-pi)Upi - (t-pi)U2pi }
= e^-piS L(t) - e^-2piS L(t + pi) <--- I think I went wrong there...
the answer should be (e^-piS / S^2) - ( e^-2piS / S^2)(1+piS)
What I'm confused about is that the c's for f(t-c)Uc do not match for the second part, so I'm wondering what is the right way of doing it. So if anyone can help, thanks.
Edit
To prevent bumping this thread up, I'll update the OP. I got the answer finally (with help from a friend in a different class, awesome
). Our DE teacher never told us it had a name, we just have a table of these things.
Anyhow,
it should be
(t - pi)Upi - (t - 2pi + pi)Up2
= e^-piS / S^2 - e^-2piS L{t-2} - pi *e^-2pi
which becomes the answer above
Thanks for helping Fenixgoon and hypn0tik!
Anyhow, I have the step function equation
f(t) =
{ 0 , t < pi
{ t - pi , pi <= t < 2pi
{ 0 , t >= 2pi
So I tried plugging it in
L{ (t-pi)Upi - (t-pi)U2pi }
= e^-piS L(t) - e^-2piS L(t + pi) <--- I think I went wrong there...
the answer should be (e^-piS / S^2) - ( e^-2piS / S^2)(1+piS)
What I'm confused about is that the c's for f(t-c)Uc do not match for the second part, so I'm wondering what is the right way of doing it. So if anyone can help, thanks.
Edit
To prevent bumping this thread up, I'll update the OP. I got the answer finally (with help from a friend in a different class, awesome
Anyhow,
it should be
(t - pi)Upi - (t - 2pi + pi)Up2
= e^-piS / S^2 - e^-2piS L{t-2} - pi *e^-2pi
which becomes the answer above
Thanks for helping Fenixgoon and hypn0tik!