Originally posted by: Zakath15
t = (arcsin x)/3
t = (arcsin y)/4
arcsin y = (4/3) arcsin x
y = sin ((4/3) arcsin x)
Originally posted by: Zakath15
t = (arcsin x)/3
t = (arcsin y)/4
arcsin y = (4/3) arcsin x
y = sin ((4/3) arcsin x)
Originally posted by: Nemesis77
well duh! She obviously wants to have sin with you! She just needs to get rid of "t" first. Who is "t"? I have no idea, boyfriend maybe?
Originally posted by: BeefJurky
and asks me a math question.... i hate math, and i've never taken multi-variable calculus, which this is apparently a preparatory problem for.... anyone know what the solution is and/or know how to do it?
x = sin (3t)
y = sin (4t)
eliminate t
Originally posted by: Zakath15
t = (arcsin x)/3
t = (arcsin y)/4
arcsin y = (4/3) arcsin x
y = sin ((4/3) arcsin x)
Originally posted by: KingNothing
This as posted by several people is correct. It's not multivariable calculus as such, it's a parametric equation. X and Y in terms of T, the elapsed time. You start by taking the inverse sine (or arcsin) of both sides, which gets the 3t and 4t outside the parens. Then you divide the respective sides by 3 and 4, and since both equations are then equal to t they're equal to themselves, and you multiply both sides by y to get the y part by itself. Then you take the sine of both sides to get just the y by itself.
