Simple math (log) problem

[jinduy]

my math is a bit fuzzy....but can someone tell me what X is, where


log(n) * X = n ?
basically i want to know how to remove the log and turn it into just n.

thanks in advance.

 

[silverpig]

10^[log(n)] = n

That should give you a start...

 

[brunswickite]

10^n = x

i think?

 

[BD2003]

1

 

[silverpig]

You COULD be lame, divide by log(n) and be left with X = n/log(n)

😀

 

[Atlantean]

n/m no idea, I was doing some calc thing for it

 

[jinduy]

let's say we're talking about log base 10...would this hold then

log z = 588

z = 10^588


?

 

[BigJ]

Originally posted by: jinduy
let's say we're talking about log base 10...would this hold then

log z = 588

z = 10^588


?

yep. here's another example

10^x = 72
x log(10) = log(72)
Since log10 = 1
x = log(72)
x = 1.857332496

Also:
log(n) * X = n
Actually the same as X log(n) = n;
Try to isolate the log by dividing by X;
log(n) = n/x
raise to the 10th power
n = 10 ^ (n/x)

Thats assuming the problem always evaluates to true.

 

[jinduy]

thanks everyone

 

[brjames]

log(n) * X = log(n^X)

 

[jinduy]

okay im on the last problem....can someone hint me how to solve
n*log(n) = 10000 ? base 2